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The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is?
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The force requirement in a blanking operation of low carbon steel shee...
Understanding Blanking Force Calculation
In a blanking operation, the force required is influenced by the sheet thickness and the area of the blanked part. The formula for calculating the blanking force (F) is given by:
F = Shear Strength * Area
Where:
- Area = π/4 * d² (for a circular blank)
- Shear Strength is a constant value for the material.
Initial Condition
- Force requirement (F1) = 5.0 kN
- Diameter (d1) = d
- Thickness (t1) = t
New Condition
The new conditions are as follows:
- New Diameter (d2) = 1.5d
- New Thickness (t2) = 0.4t
Area Calculation
To find the new force (F2), we first calculate the new area:
- New Area (A2) = π/4 * (d2)²
- A2 = π/4 * (1.5d)² = π/4 * 2.25d² = 2.25 * (π/4 * d²)
Force Calculation
Now we relate the forces using the areas:
- F1 = Shear Strength * A1
- F2 = Shear Strength * A2
Since A1 = π/4 * d², we can express F2 in terms of F1:
F2 = Shear Strength * 2.25 * (π/4 * d²) = 2.25 * F1
Final Calculation
Substituting the known value of F1:
F2 = 2.25 * 5.0 kN = 11.25 kN
Conclusion
The new blanking force required is 11.25 kN when the diameter is increased to 1.5d and the thickness is reduced to 0.4t.
In a blanking operation, the force required is influenced by the sheet thickness and the area of the blanked part. The formula for calculating the blanking force (F) is given by:
F = Shear Strength * Area
Where:
- Area = π/4 * d² (for a circular blank)
- Shear Strength is a constant value for the material.
Initial Condition
- Force requirement (F1) = 5.0 kN
- Diameter (d1) = d
- Thickness (t1) = t
New Condition
The new conditions are as follows:
- New Diameter (d2) = 1.5d
- New Thickness (t2) = 0.4t
Area Calculation
To find the new force (F2), we first calculate the new area:
- New Area (A2) = π/4 * (d2)²
- A2 = π/4 * (1.5d)² = π/4 * 2.25d² = 2.25 * (π/4 * d²)
Force Calculation
Now we relate the forces using the areas:
- F1 = Shear Strength * A1
- F2 = Shear Strength * A2
Since A1 = π/4 * d², we can express F2 in terms of F1:
F2 = Shear Strength * 2.25 * (π/4 * d²) = 2.25 * F1
Final Calculation
Substituting the known value of F1:
F2 = 2.25 * 5.0 kN = 11.25 kN
Conclusion
The new blanking force required is 11.25 kN when the diameter is increased to 1.5d and the thickness is reduced to 0.4t.
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The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is?
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The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is?.
The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is?.
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The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is?, a detailed solution for The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is? has been provided alongside types of The force requirement in a blanking operation of low carbon steel sheet is 5.0 kN. The thickness of the sheet is 't and diameter of the blanked part is 'd. For the same work material, if the diameter of the blanked part is increased to 1.5d and thickness is reduced to 0.4t, the new blanking force in kN is? theory, EduRev gives you an
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