NEET Exam  >  NEET Questions  >   Methanol is industrially prepared bya)oxidat... Start Learning for Free
Methanol is industrially prepared by
  • a)
    oxidation of CH4 by steam at 900°C
  • b)
    reduction of HCHO using LiAlH4
  • c)
    reaction HCHO with a solution of NaOH
  • d)
    reduction of CO using H2 and ZnO – Cr2O3.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Methanol is industrially prepared bya)oxidation of CH4 by steam at 90...
Methanol is prepared commercially from water gas which is a mixture of carbon monoxide and hydrogen. In this method, water gas is mixed with its half volume of hydrogen and is passed over a heated Cr2O3 - ZnO catalyst at 673 K under high pressure.
View all questions of this test
Most Upvoted Answer
Methanol is industrially prepared bya)oxidation of CH4 by steam at 90...
Methanol is industrially prepared by reduction of CO using H2 and ZnO – Cr2O3.

Methanol, also known as methyl alcohol, is an important organic compound used as a solvent, fuel, and raw material in various industries. It is commonly produced industrially through a process called the catalytic synthesis of methanol.

The correct answer to the given question is option 'D', which states that methanol is prepared by the reduction of CO (carbon monoxide) using H2 (hydrogen) and ZnO – Cr2O3 (zinc oxide – chromium oxide) as catalysts.

Process:

The industrial synthesis of methanol involves several steps, including the following key reactions:

1. Water-gas shift reaction:
CO + H2O ⇌ CO2 + H2

This reaction is carried out to generate hydrogen gas (H2) and carbon dioxide (CO2) from carbon monoxide (CO) and water (H2O). It is an exothermic reaction that occurs at high temperatures in the presence of a suitable catalyst, such as iron oxide.

2. Methanol synthesis:
CO + 2H2 ⇌ CH3OH

In this step, the generated hydrogen gas from the water-gas shift reaction reacts with carbon monoxide to produce methanol. This reaction is known as the methanol synthesis reaction and is catalyzed by a mixture of zinc oxide (ZnO) and chromium oxide (Cr2O3). The catalyst helps in increasing the rate of the reaction and enhancing the selectivity towards methanol formation.

Explanation of the correct option:

Option 'D' states that methanol is prepared by the reduction of CO using H2 and ZnO – Cr2O3. This is the correct answer because the reduction of CO with hydrogen gas in the presence of a suitable catalyst (ZnO – Cr2O3) is a well-established method for the industrial production of methanol. This process allows for the conversion of CO, a byproduct of various industrial processes, into a valuable and versatile chemical compound like methanol.

This method has been widely adopted due to the efficiency and selectivity of the catalyst system, which promotes the formation of methanol while minimizing the formation of unwanted byproducts. The ZnO – Cr2O3 catalyst provides an active surface for the reaction and helps in the dissociation of CO and the subsequent formation of methanol.

By using this process, a large-scale production of methanol can be achieved, meeting the demand for this important chemical compound in various industries.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Similar NEET Doubts

Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in which of the following solvents?

Top Courses for NEET

Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer?
Question Description
Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer?.
Solutions for Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Methanol is industrially prepared bya)oxidation of CH4 by steam at 900°Cb)reduction of HCHO using LiAlH4c)reaction HCHO with a solution of NaOHd)reduction of CO using H2 and ZnO – Cr2O3.Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev