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The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely
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The molality of the solution prepared by dissolving 125ml of pure meth...
Calculating Molality of the Solution:
To calculate the molality of the solution, we first need to determine the moles of solute (methanol) and the mass of solvent (ethanol).

Step 1: Calculate Moles of Methanol:
Given that the density of methanol is 0.8 g/ml, we can calculate the mass of methanol:
Volume of methanol = 125 ml
Density of methanol = 0.8 g/ml
Mass of methanol = Volume x Density = 125 ml x 0.8 g/ml = 100 g
Next, we need to convert the mass of methanol to moles using its molar mass:
Molar mass of methanol (CH3OH) = 32 g/mol
Moles of methanol = Mass / Molar mass = 100 g / 32 g/mol = 3.125 mol

Step 2: Calculate Mass of Ethanol:
Given that the mass of ethanol is 375 g, we can directly use this value as the mass of the solvent.

Step 3: Calculate Molality of the Solution:
Molality (m) is defined as moles of solute per kilogram of solvent. Since the mass of ethanol is in grams, we need to convert it to kilograms:
Mass of ethanol = 375 g = 0.375 kg
Now, we can calculate the molality of the solution using the formula:
Molality (m) = Moles of solute / Mass of solvent in kg
Molality = 3.125 mol / 0.375 kg = 8.33 mol/kg
Therefore, the molality of the solution prepared by dissolving 125 ml of pure methanol in 375 g of ethanol is 8.33 mol/kg.
Community Answer
The molality of the solution prepared by dissolving 125ml of pure meth...
8.400 m
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