NEET Exam > NEET Questions > A solution prepared by dissolving 2.8 gm of l...
Start Learning for Free
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer?
Most Upvoted Answer
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water...
Community Answer
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water...
Calculation of moles of CaO:
To determine the moles of CaO, we need to use the formula:
moles = mass / molar mass
The molar mass of CaO is 56.08 g/mol. Therefore, the moles of CaO can be calculated as follows:
moles of CaO = 2.8 g / 56.08 g/mol = 0.05 mol
Calculation of moles of Ca(OH)2:
Since CaO reacts with water to form Ca(OH)2, the moles of Ca(OH)2 can be determined by using the stoichiometry of the reaction.
The balanced equation for the reaction is:
CaO + H2O → Ca(OH)2
From the equation, we can see that 1 mol of CaO reacts to form 1 mol of Ca(OH)2.
Therefore, the moles of Ca(OH)2 are also 0.05 mol.
Calculation of concentration of Ca(OH)2:
To find the concentration of Ca(OH)2 in the solution, we divide the moles of Ca(OH)2 by the volume of the solution in liters.
Given that the volume of the solution is 1 L, the concentration of Ca(OH)2 can be calculated as follows:
concentration of Ca(OH)2 = moles of Ca(OH)2 / volume of solution
concentration of Ca(OH)2 = 0.05 mol / 1 L = 0.05 mol/L
Calculation of solubility of Ca(OH)2:
The solubility of Ca(OH)2 in water is given as 1.48 g/L.
Calculation of pH:
The pH of a solution can be determined using the equation:
pOH = -log10(concentration of hydroxide ions)
Since Ca(OH)2 dissociates to form two moles of hydroxide ions for every mole of Ca(OH)2, the concentration of hydroxide ions can be calculated as follows:
concentration of hydroxide ions = 2 * concentration of Ca(OH)2
concentration of hydroxide ions = 2 * 0.05 mol/L = 0.1 mol/L
Now, we can calculate the pOH:
pOH = -log10(0.1) ≈ 1
Since pH + pOH = 14, we can calculate the pH as:
pH = 14 - pOH = 14 - 1 = 13
Therefore, the pH of the solution obtained is 13, which is not the correct answer according to the given options. Hence, there may be an error in the provided answer choices or calculations.
To determine the moles of CaO, we need to use the formula:
moles = mass / molar mass
The molar mass of CaO is 56.08 g/mol. Therefore, the moles of CaO can be calculated as follows:
moles of CaO = 2.8 g / 56.08 g/mol = 0.05 mol
Calculation of moles of Ca(OH)2:
Since CaO reacts with water to form Ca(OH)2, the moles of Ca(OH)2 can be determined by using the stoichiometry of the reaction.
The balanced equation for the reaction is:
CaO + H2O → Ca(OH)2
From the equation, we can see that 1 mol of CaO reacts to form 1 mol of Ca(OH)2.
Therefore, the moles of Ca(OH)2 are also 0.05 mol.
Calculation of concentration of Ca(OH)2:
To find the concentration of Ca(OH)2 in the solution, we divide the moles of Ca(OH)2 by the volume of the solution in liters.
Given that the volume of the solution is 1 L, the concentration of Ca(OH)2 can be calculated as follows:
concentration of Ca(OH)2 = moles of Ca(OH)2 / volume of solution
concentration of Ca(OH)2 = 0.05 mol / 1 L = 0.05 mol/L
Calculation of solubility of Ca(OH)2:
The solubility of Ca(OH)2 in water is given as 1.48 g/L.
Calculation of pH:
The pH of a solution can be determined using the equation:
pOH = -log10(concentration of hydroxide ions)
Since Ca(OH)2 dissociates to form two moles of hydroxide ions for every mole of Ca(OH)2, the concentration of hydroxide ions can be calculated as follows:
concentration of hydroxide ions = 2 * concentration of Ca(OH)2
concentration of hydroxide ions = 2 * 0.05 mol/L = 0.1 mol/L
Now, we can calculate the pOH:
pOH = -log10(0.1) ≈ 1
Since pH + pOH = 14, we can calculate the pH as:
pH = 14 - pOH = 14 - 1 = 13
Therefore, the pH of the solution obtained is 13, which is not the correct answer according to the given options. Hence, there may be an error in the provided answer choices or calculations.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer?
Question Description
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer?.
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer?.
Solutions for A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer?, a detailed solution for A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? has been provided alongside types of A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water to make 1 lit. of lime water (Ca(OH)2) . If solubility of Ca(OH)2 in water is 1.48gm/lit. The pH of the solution obtained will be - (A) 12.3 ( B)12.6 (C) 1.3 (D)13 Correct answer is (B) . Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup