A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water...
A solution prepared by dissolving 2.8 gm of lime (CaO) in enough water...
Calculation of moles of CaO:
To determine the moles of CaO, we need to use the formula:
moles = mass / molar mass
The molar mass of CaO is 56.08 g/mol. Therefore, the moles of CaO can be calculated as follows:
moles of CaO = 2.8 g / 56.08 g/mol = 0.05 mol
Calculation of moles of Ca(OH)2:
Since CaO reacts with water to form Ca(OH)2, the moles of Ca(OH)2 can be determined by using the stoichiometry of the reaction.
The balanced equation for the reaction is:
CaO + H2O → Ca(OH)2
From the equation, we can see that 1 mol of CaO reacts to form 1 mol of Ca(OH)2.
Therefore, the moles of Ca(OH)2 are also 0.05 mol.
Calculation of concentration of Ca(OH)2:
To find the concentration of Ca(OH)2 in the solution, we divide the moles of Ca(OH)2 by the volume of the solution in liters.
Given that the volume of the solution is 1 L, the concentration of Ca(OH)2 can be calculated as follows:
concentration of Ca(OH)2 = moles of Ca(OH)2 / volume of solution
concentration of Ca(OH)2 = 0.05 mol / 1 L = 0.05 mol/L
Calculation of solubility of Ca(OH)2:
The solubility of Ca(OH)2 in water is given as 1.48 g/L.
Calculation of pH:
The pH of a solution can be determined using the equation:
pOH = -log10(concentration of hydroxide ions)
Since Ca(OH)2 dissociates to form two moles of hydroxide ions for every mole of Ca(OH)2, the concentration of hydroxide ions can be calculated as follows:
concentration of hydroxide ions = 2 * concentration of Ca(OH)2
concentration of hydroxide ions = 2 * 0.05 mol/L = 0.1 mol/L
Now, we can calculate the pOH:
pOH = -log10(0.1) ≈ 1
Since pH + pOH = 14, we can calculate the pH as:
pH = 14 - pOH = 14 - 1 = 13
Therefore, the pH of the solution obtained is 13, which is not the correct answer according to the given options. Hence, there may be an error in the provided answer choices or calculations.
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