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Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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the NEET exam syllabus. Information about Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam.
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Here you can find the meaning of Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R1 > R1). If the potential difference across the source having internal resistance R2 is zero, thena)R = R2 - R1b)R = R2 x (R1 + R2) /(R2 - R1)c)R = R1R2 /(R2 - R1)d)R = R1R2 /(R1 - R2)Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.