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Two cells of the same emf E but different internal resistances r1 and r2 are connected in series to an external resistance R. The value of R, for which the potential difference across the first cell is zero, is given by
  • a)
    R = r1 - r2
  • b)
    R = r1 + r2
  • c)
    R = r1r2
  • d)
    R = r1/r2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Two cells of the same emf E but different internal resistances r1and r...
Net resistance of the circuit = r1 + r2 + R
Net emf in series = E + E = 2E
Therefore, from Ohm's law, current in the circuit

It is given that, as circuit is closed, potential difference across the first cell is zero. That is,

From Equations (i) and (ii), we get

R = external resistance = r1 - r2
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Two cells of the same emf E but different internal resistances r1and r2are connected in series to an external resistance R. The value of R, for which the potential difference across the first cell is zero, is given bya)R = r1- r2b)R = r1+ r2c)R = r1r2d)R = r1/r2Correct answer is option 'A'. Can you explain this answer?
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