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For an octahedral complex, which of the following d-electron configuration will give maximum CFSE?
- a)High spin with d6 configuration
- b)Low spin with d4 configuration
- c)Low spin with d5 configuration
- d)High spin with d7 configuration
Correct answer is option 'C'. Can you explain this answer?
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For an octahedral complex, which of the following d-electron configur...
(a) High spin with d6 configuration
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(b) Low spin with d4 configuration
(c) Low spin with d5 configuration
(d) High spin with d7 configuration
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For an octahedral complex, which of the following d-electron configur...
Octahedral Complex and CFSE
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In order to determine which d-electron configuration will give maximum Crystal Field Stabilization Energy (CFSE) in an octahedral complex, we need to consider the concept of high spin and low spin configurations.
High spin and low spin configurations
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In an octahedral complex, the d-electrons can be arranged in two different ways: high spin and low spin configurations.
- High spin configuration: In a high spin configuration, the d-electrons occupy the available d-orbitals in such a way that maximum number of unpaired electrons are present. This configuration is preferred when the energy required to pair up the electrons is greater than the energy difference between the t2g and eg orbitals.
- Low spin configuration: In a low spin configuration, the d-electrons occupy the available d-orbitals in such a way that minimum number of unpaired electrons are present. This configuration is preferred when the energy required to pair up the electrons is less than the energy difference between the t2g and eg orbitals.
Determining the maximum CFSE
--------------------------------------
The CFSE of a complex is determined by the arrangement of electrons in the d-orbitals and the energy difference between the t2g and eg orbitals. The CFSE is given by the formula:
CFSE = -0.4 * (n * Δo) + 0.6 * (n * Δt)
where n is the number of unpaired electrons, Δo is the energy difference between the t2g and eg orbitals in a high spin configuration, and Δt is the energy difference between the t2g and eg orbitals in a low spin configuration.
From the formula, we can see that the CFSE is dependent on the number of unpaired electrons. Therefore, the configuration that will give maximum CFSE is the one with the maximum number of unpaired electrons.
Answer: Low spin with d5 configuration
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According to the given options, the low spin configuration with d5 electrons (option C) will have maximum CFSE. This is because in a low spin configuration, the d-electrons will pair up in such a way that only one electron is unpaired, resulting in a total of 5 unpaired electrons. This is greater than the number of unpaired electrons in the other options.
By selecting the low spin configuration with d5 electrons, we maximize the number of unpaired electrons, leading to maximum CFSE.
--------------------------------------
In order to determine which d-electron configuration will give maximum Crystal Field Stabilization Energy (CFSE) in an octahedral complex, we need to consider the concept of high spin and low spin configurations.
High spin and low spin configurations
--------------------------------------
In an octahedral complex, the d-electrons can be arranged in two different ways: high spin and low spin configurations.
- High spin configuration: In a high spin configuration, the d-electrons occupy the available d-orbitals in such a way that maximum number of unpaired electrons are present. This configuration is preferred when the energy required to pair up the electrons is greater than the energy difference between the t2g and eg orbitals.
- Low spin configuration: In a low spin configuration, the d-electrons occupy the available d-orbitals in such a way that minimum number of unpaired electrons are present. This configuration is preferred when the energy required to pair up the electrons is less than the energy difference between the t2g and eg orbitals.
Determining the maximum CFSE
--------------------------------------
The CFSE of a complex is determined by the arrangement of electrons in the d-orbitals and the energy difference between the t2g and eg orbitals. The CFSE is given by the formula:
CFSE = -0.4 * (n * Δo) + 0.6 * (n * Δt)
where n is the number of unpaired electrons, Δo is the energy difference between the t2g and eg orbitals in a high spin configuration, and Δt is the energy difference between the t2g and eg orbitals in a low spin configuration.
From the formula, we can see that the CFSE is dependent on the number of unpaired electrons. Therefore, the configuration that will give maximum CFSE is the one with the maximum number of unpaired electrons.
Answer: Low spin with d5 configuration
-------------------------------------------
According to the given options, the low spin configuration with d5 electrons (option C) will have maximum CFSE. This is because in a low spin configuration, the d-electrons will pair up in such a way that only one electron is unpaired, resulting in a total of 5 unpaired electrons. This is greater than the number of unpaired electrons in the other options.
By selecting the low spin configuration with d5 electrons, we maximize the number of unpaired electrons, leading to maximum CFSE.
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For an octahedral complex, which of the following d-electron configuration will give maximum CFSE?a)High spin with d6 configurationb)Low spin with d4 configurationc)Low spin with d5 configurationd)High spin with d7 configurationCorrect answer is option 'C'. Can you explain this answer?
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