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Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:
- a)200
- b)150
- c)400
- d)360
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Using a nuclear counter the count rate of emitted particles from a ra...
Given Data:
- Initial count rate (t=0): 1600 counts per second
- Count rate at t=8 seconds: 100 counts per second
Calculating Decay Constant:
- Using the formula for radioactive decay: N = N0 * e^(-λt), where N is the final count rate, N0 is the initial count rate, λ is the decay constant, and t is time.
- Substituting the values, we get: 100 = 1600 * e^(-8λ)
- Simplifying, we find: e^(-8λ) = 1/16
- Taking natural logarithm on both sides: -8λ = ln(1/16)
- Solving for decay constant, we get: λ = ln(16)/8 ≈ 0.1155
Calculating Count Rate at t=6 seconds:
- Using the decay constant calculated above: N = N0 * e^(-λt)
- Substituting the values for t=6 seconds: N = 1600 * e^(-0.1155*6) ≈ 200 counts per second
Therefore, the count rate observed at t=6 seconds is close to 200 counts per second, which corresponds to option 'A'.
- Initial count rate (t=0): 1600 counts per second
- Count rate at t=8 seconds: 100 counts per second
Calculating Decay Constant:
- Using the formula for radioactive decay: N = N0 * e^(-λt), where N is the final count rate, N0 is the initial count rate, λ is the decay constant, and t is time.
- Substituting the values, we get: 100 = 1600 * e^(-8λ)
- Simplifying, we find: e^(-8λ) = 1/16
- Taking natural logarithm on both sides: -8λ = ln(1/16)
- Solving for decay constant, we get: λ = ln(16)/8 ≈ 0.1155
Calculating Count Rate at t=6 seconds:
- Using the decay constant calculated above: N = N0 * e^(-λt)
- Substituting the values for t=6 seconds: N = 1600 * e^(-0.1155*6) ≈ 200 counts per second
Therefore, the count rate observed at t=6 seconds is close to 200 counts per second, which corresponds to option 'A'.
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Community Answer
Using a nuclear counter the count rate of emitted particles from a ra...
According to question, at t = 0, A0 = 
=1600 C/s
and at t = 8s, A = 100 C/s
Therefore half life period, t1/2 = 2s
∴ Activity at t = 6s = 1600 
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Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer?
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Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer?.
Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer?.
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Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:a)200b)150c)400d)360Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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