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A body of mass 50 kg slides over a horizontal distance of 1 m. If coefficient of friction between their surfaces is 0.2, then work done against friction is
  • a)
    98 J
  • b)
    72 J
  • c)
    56 J
  • d)
    34 J
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body of mass 50 kg slides over a horizontal distance of 1 m. If coef...
To calculate the work done against friction, we need to consider the equation:

Work done = Force × Distance

1. Calculate the frictional force:

The frictional force can be calculated using the equation:

Frictional force = coefficient of friction × Normal force

The normal force can be calculated using the equation:

Normal force = mass × gravity

Where gravity is the acceleration due to gravity, approximately equal to 9.8 m/s^2.

Normal force = 50 kg × 9.8 m/s^2 = 490 N

Frictional force = 0.2 × 490 N = 98 N

2. Calculate the work done against friction:

Work done against friction = frictional force × distance

Work done against friction = 98 N × 1 m = 98 J

Therefore, the correct answer is option A) 98 J.
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Community Answer
A body of mass 50 kg slides over a horizontal distance of 1 m. If coef...
Body slide kar Rahi hai to kinetic friction lagega Jo ki static se Kam hota hai.
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A body of mass 50 kg slides over a horizontal distance of 1 m. If coefficient of friction between their surfaces is 0.2, then work done against friction isa)98 Jb)72 Jc)56 Jd)34 JCorrect answer is option 'A'. Can you explain this answer?
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