NEET Exam > NEET Questions > 6 litres of an ideal gas expands isothermally...
Start Learning for Free
6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?
- a)30 Newton metre
- b)80 Newton metre
- c)50 Newton metres
- d)20 Newton metre
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
6 litres of an ideal gas expands isothermally at a temperature of 300 ...
Given:
Initial volume of gas (V1) = 6 litres
Final volume of gas (V2) = 10 litres
Temperature (T) = 300 Kelvin
Pressure (P) = 5 atm
To find: Work done (W)
The work done by an ideal gas during an isothermal expansion can be calculated using the formula:
W = nRT ln(V2/V1)
Where:
n = number of moles of gas
R = ideal gas constant (8.314 J/mol·K)
ln = natural logarithm
V1 = initial volume of gas
V2 = final volume of gas
To find the number of moles (n), we can use the ideal gas equation:
PV = nRT
Rearranging the equation, we have:
n = PV / RT
Substituting the given values:
n = (5 atm * 6 liters) / (0.0821 atm·L/mol·K * 300 K)
n ≈ 0.98 moles
Substituting the values of n, R, V1, and V2 into the formula for work done:
W = (0.98 mol * 8.314 J/mol·K * 300 K) ln(10 L / 6 L)
W ≈ 19.6 J ln(10/6)
W ≈ 19.6 J ln(5/3)
W ≈ 19.6 J ln(1.67)
W ≈ 19.6 J * 0.51
W ≈ 9.996 J
W ≈ 10 J
Therefore, the work done by the gas during the isothermal expansion is approximately 10 Joules.
Initial volume of gas (V1) = 6 litres
Final volume of gas (V2) = 10 litres
Temperature (T) = 300 Kelvin
Pressure (P) = 5 atm
To find: Work done (W)
The work done by an ideal gas during an isothermal expansion can be calculated using the formula:
W = nRT ln(V2/V1)
Where:
n = number of moles of gas
R = ideal gas constant (8.314 J/mol·K)
ln = natural logarithm
V1 = initial volume of gas
V2 = final volume of gas
To find the number of moles (n), we can use the ideal gas equation:
PV = nRT
Rearranging the equation, we have:
n = PV / RT
Substituting the given values:
n = (5 atm * 6 liters) / (0.0821 atm·L/mol·K * 300 K)
n ≈ 0.98 moles
Substituting the values of n, R, V1, and V2 into the formula for work done:
W = (0.98 mol * 8.314 J/mol·K * 300 K) ln(10 L / 6 L)
W ≈ 19.6 J ln(10/6)
W ≈ 19.6 J ln(5/3)
W ≈ 19.6 J ln(1.67)
W ≈ 19.6 J * 0.51
W ≈ 9.996 J
W ≈ 10 J
Therefore, the work done by the gas during the isothermal expansion is approximately 10 Joules.
Free Test
FREE
| Start Free Test |
Community Answer
6 litres of an ideal gas expands isothermally at a temperature of 300 ...
The expression for work done is given by pressure x volume difference, here an ideal gas has a volume difference of 4 litres at 5 ATM pressure. So the work done = 10 – 6 liters x 5atm = 20 Newton metre.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer?
Question Description
6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer?.
6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer?.
Solutions for 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice 6 litres of an ideal gas expands isothermally at a temperature of 300 Kelvin up to 10 litres at a pressure of 5 atm, what is the work done?a)30 Newton metreb)80 Newton metrec)50 Newton metresd)20 Newton metreCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup