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A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ?
( Ans. 2.0 × 10 power 4 J)?
( Ans. 2.0 × 10 power 4 J)?
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A gas expands from 75 litre to 125 litre at a constant pressure of 4 a...
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A gas expands from 75 litre to 125 litre at a constant pressure of 4 a...
**Given:**
Initial volume (Vi) = 75 liters
Final volume (Vf) = 125 liters
Initial pressure (Pi) = 4 atm
One atmospheric pressure (Pa) = 1 × 10^5 Pa
**To find:**
Work done by the gas during the expansion (W)
**Formula:**
The work done by a gas during an expansion can be calculated using the formula:
W = PΔV
Where:
W = Work done by the gas
P = Pressure
ΔV = Change in volume
**Solution:**
1. Convert the given volumes from liters to cubic meters:
Vi = 75 liters = 75 × 10^-3 m^3
Vf = 125 liters = 125 × 10^-3 m^3
2. Convert the given pressure from atm to Pa:
Pi = 4 atm = 4 × 1 × 10^5 Pa
3. Calculate the change in volume:
ΔV = Vf - Vi = (125 × 10^-3) m^3 - (75 × 10^-3) m^3 = 50 × 10^-3 m^3
4. Substitute the values into the formula and calculate the work done:
W = PΔV = (4 × 1 × 10^5 Pa)(50 × 10^-3 m^3)
W = 4 × 50 × 10^2 J
W = 2 × 10^3 J
W = 2.0 × 10^4 J
**Answer:**
The work done by the gas during the expansion is 2.0 × 10^4 J.
Initial volume (Vi) = 75 liters
Final volume (Vf) = 125 liters
Initial pressure (Pi) = 4 atm
One atmospheric pressure (Pa) = 1 × 10^5 Pa
**To find:**
Work done by the gas during the expansion (W)
**Formula:**
The work done by a gas during an expansion can be calculated using the formula:
W = PΔV
Where:
W = Work done by the gas
P = Pressure
ΔV = Change in volume
**Solution:**
1. Convert the given volumes from liters to cubic meters:
Vi = 75 liters = 75 × 10^-3 m^3
Vf = 125 liters = 125 × 10^-3 m^3
2. Convert the given pressure from atm to Pa:
Pi = 4 atm = 4 × 1 × 10^5 Pa
3. Calculate the change in volume:
ΔV = Vf - Vi = (125 × 10^-3) m^3 - (75 × 10^-3) m^3 = 50 × 10^-3 m^3
4. Substitute the values into the formula and calculate the work done:
W = PΔV = (4 × 1 × 10^5 Pa)(50 × 10^-3 m^3)
W = 4 × 50 × 10^2 J
W = 2 × 10^3 J
W = 2.0 × 10^4 J
**Answer:**
The work done by the gas during the expansion is 2.0 × 10^4 J.
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A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)?
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A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)?.
A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas expands from 75 litre to 125 litre at a constant pressure of 4 atmospheric. If one atmospheric pressure is 1×10 power 5 Pa ( N m -2) , Calculate the work done by the gas during this expansion ? ( Ans. 2.0 × 10 power 4 J)?.
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