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The tangential velocity in a circular motion change as v = 2t2 – 7 with the radius being equal to 3 m. What is the angular velocity at t = 1 s in rad/s?
- a)-5/3
- b)-2/3
- c)3
- d)-3/5
Correct answer is option 'A'. Can you explain this answer?
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The tangential velocity in a circular motion change as v = 2t2– ...
The angular velocity is given as, ω = v/r. Hence, the function for angular velocity is ω = (2t2 – 7)/3. On substituting, the suitable values, we will get the angular velocity as -5/3 rad/s.
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The tangential velocity in a circular motion change as v = 2t2– ...
The formula you provided, v = 2t^2, represents the relationship between the tangential velocity (v) and time (t) in a circular motion. This equation suggests that the tangential velocity is directly proportional to the square of time.
In this case, as time increases, the tangential velocity also increases. However, it is important to note that the rate of increase is not constant. The tangential velocity increases quadratically with time, meaning that it will accelerate faster and faster as time progresses.
In this case, as time increases, the tangential velocity also increases. However, it is important to note that the rate of increase is not constant. The tangential velocity increases quadratically with time, meaning that it will accelerate faster and faster as time progresses.
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The tangential velocity in a circular motion change as v = 2t2– 7 with the radius being equal to 3 m. What is the angular velocity at t = 1 s in rad/s?a)-5/3b)-2/3c)3d)-3/5Correct answer is option 'A'. Can you explain this answer?
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