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You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!?
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You are given several identical resistors each of value 5ohm and each ...
Explanation:
Step 1: Calculate the resistance required.
Given, resistance required = 2.5ohm
Maximum current required = 4A
Using Ohm's Law, we can calculate the power required.
Power = I^2 * R = 4^2 * 2.5 = 40W
Step 2: Identify the minimum number of resistors required.
To calculate the number of resistors required, we can use the formula:
N = Rtotal / Rsingle
where N is the number of resistors required, Rtotal is the total resistance required and Rsingle is the resistance of one resistor.
Substituting the values, we get:
N = 2.5 / 5 = 0.5
Since the number of resistors must be a whole number, we need to round up to the nearest integer, which is 1.
Therefore, the minimum number of resistors required is 1.
Step 3: Check if the selected resistors can handle the current.
Since each resistor can handle a maximum current of 2A, we need to ensure that the selected resistors can handle the required current of 4A.
Since we are using only one resistor, we can simply check if it can handle the current. Since 4A is greater than 2A, the selected resistors cannot handle the current.
Step 4: Select the required number of resistors.
Since we need a resistance of 2.5ohm and the resistance of each resistor is 5ohm, we can connect two resistors in parallel to get a resistance of 2.5ohm.
Connecting two resistors in parallel would result in a resistance of:
R = (R1 * R2) / (R1 + R2)
R = (5 * 5) / (5 + 5)
R = 2.5ohm
Since each resistor can handle a maximum current of 2A, connecting two resistors in parallel would result in a maximum current of:
I = I1 + I2
I = 2A + 2A
I = 4A
Therefore, the minimum number of resistors required is 2.
Conclusion:
In conclusion, to produce a resistance of 2.5ohm which can carry a current of 4A, we need a minimum of 2 resistors.
Step 1: Calculate the resistance required.
Given, resistance required = 2.5ohm
Maximum current required = 4A
Using Ohm's Law, we can calculate the power required.
Power = I^2 * R = 4^2 * 2.5 = 40W
Step 2: Identify the minimum number of resistors required.
To calculate the number of resistors required, we can use the formula:
N = Rtotal / Rsingle
where N is the number of resistors required, Rtotal is the total resistance required and Rsingle is the resistance of one resistor.
Substituting the values, we get:
N = 2.5 / 5 = 0.5
Since the number of resistors must be a whole number, we need to round up to the nearest integer, which is 1.
Therefore, the minimum number of resistors required is 1.
Step 3: Check if the selected resistors can handle the current.
Since each resistor can handle a maximum current of 2A, we need to ensure that the selected resistors can handle the required current of 4A.
Since we are using only one resistor, we can simply check if it can handle the current. Since 4A is greater than 2A, the selected resistors cannot handle the current.
Step 4: Select the required number of resistors.
Since we need a resistance of 2.5ohm and the resistance of each resistor is 5ohm, we can connect two resistors in parallel to get a resistance of 2.5ohm.
Connecting two resistors in parallel would result in a resistance of:
R = (R1 * R2) / (R1 + R2)
R = (5 * 5) / (5 + 5)
R = 2.5ohm
Since each resistor can handle a maximum current of 2A, connecting two resistors in parallel would result in a maximum current of:
I = I1 + I2
I = 2A + 2A
I = 4A
Therefore, the minimum number of resistors required is 2.
Conclusion:
In conclusion, to produce a resistance of 2.5ohm which can carry a current of 4A, we need a minimum of 2 resistors.
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You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!?
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You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!?.
You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!?.
Solutions for You are given several identical resistors each of value 5ohm and each capable of carrying a maximum current of 2A. It is required to make a suitable combination of these resistances to produce a resistance of 2.5ohm which can carry current of 4A. The minimum number of resistances required for this job is. a)2 b)4 c)6 d)8 The correct answer is opt 'a' - 2. Explain how?!? in English & in Hindi are available as part of our courses for NEET.
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