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Three identical cells each of e.m.f. 2 V and unknown internal resistances are connected in parallel. This combination is connected to a 5 Ω resistor. If the terminal voltage across the cell is 1.5 V, then internal resistance of each cell is
  • a)
    3 Ω
  • b)
    4 Ω
  • c)
    5 Ω
  • d)
    6 Ω
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Three identical cells each of e.m.f. 2 V and unknown internal resistan...
Given Information:
- Three identical cells each of e.m.f. 2 V and unknown internal resistances are connected in parallel.
- The combination is connected to a 5 Ω resistor.
- The terminal voltage across the cell is 1.5 V.

To Find: Internal resistance of each cell.

Solution:
Let the internal resistance of each cell be r.

Formula used:
- Terminal voltage (Vt) = e.m.f. (E) - (internal resistance (r) x current (I))
- Total resistance (R) = (r/n) + Rext
- Current (I) = E/R

Where, n = number of cells.

Calculation:
Given,
- E = 2 V
- Rext = 5 Ω
- Vt = 1.5 V
- n = 3

Using the formula,
I = E/R = 2/(r/3 + 5) = 6/(r+15)

Vt = E - Ir = 2 - 6r/(r+15) = 1.5

Solving for r, we get r = 5 Ω.

Therefore, the internal resistance of each cell is 5 Ω.

Final Answer: Internal resistance of each cell is 5 Ω.
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Three identical cells each of e.m.f. 2 V and unknown internal resistan...
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Three identical cells each of e.m.f. 2 V and unknown internal resistances are connected in parallel. This combination is connected to a 5 Ω resistor. If the terminal voltage across the cell is 1.5 V, then internal resistance of each cell isa)3 Ωb)4 Ωc)5 Ωd)6 ΩCorrect answer is option 'C'. Can you explain this answer?
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