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Three resistances 2Ω, 4Ω, 5Ω are combined in series and this combination is connected to a battery of 12 V emf and negligible internal resistance. The potential drop across these resistances are
  • a)
    (5,45,4.36,2.18)V
  • b)
    (2,18,5.45,4.36)V
  • c)
    (4.36,2.18,5.45)V
  • d)
    (2.18,4.36,5.45)V
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Three resistances 2Ω, 4Ω, 5Ω are combined in series ...

Let current in the circuit is I. Then total resistance in the circuit.
R = R1 + R2 + R3 = 2 + 4 + 5 = 11Ω
∴ 
The potential drop across 2Ω resistance

The potential drop across 4Ω resistance

The potential drop across 5Ω resistance

Hence(V1, V2, V3) = (2.18, 4.36, 5.45)V
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Three resistances 2Ω, 4Ω, 5Ω are combined in series and this combination is connected to a battery of 12 V emf and negligible internal resistance. The potential drop across these resistances area)(5,45,4.36,2.18)Vb)(2,18,5.45,4.36)Vc)(4.36,2.18,5.45)Vd)(2.18,4.36,5.45)VCorrect answer is option 'D'. Can you explain this answer?
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