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If 315cal of heat is given to the system, and the system does 20cal of work, find the change in internal energy.
- a)295cal
- b)335cal
- c)0 cal
- d)335J
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
If 315cal of heat is given to the system, and the system does 20cal of...
Given information:
Heat (q) = 315 cal
Work (w) = 20 cal
To find:
Change in internal energy (ΔU)
Formula:
The first law of thermodynamics states that the change in internal energy of a system (ΔU) is equal to the heat added to the system (q) minus the work done by the system (w).
ΔU = q - w
Calculation:
Given that q = 315 cal and w = 20 cal, we can substitute these values into the formula:
ΔU = 315 cal - 20 cal
ΔU = 295 cal
Therefore, the change in internal energy (ΔU) is 295 cal.
Heat (q) = 315 cal
Work (w) = 20 cal
To find:
Change in internal energy (ΔU)
Formula:
The first law of thermodynamics states that the change in internal energy of a system (ΔU) is equal to the heat added to the system (q) minus the work done by the system (w).
ΔU = q - w
Calculation:
Given that q = 315 cal and w = 20 cal, we can substitute these values into the formula:
ΔU = 315 cal - 20 cal
ΔU = 295 cal
Therefore, the change in internal energy (ΔU) is 295 cal.
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Community Answer
If 315cal of heat is given to the system, and the system does 20cal of...
The first law states that ΔU=ΔQ – ΔW
= 315 – 20
= 295cal.
Work is positive as it is done by the system. Heat is positive as it is supplied to the system.
= 315 – 20
= 295cal.
Work is positive as it is done by the system. Heat is positive as it is supplied to the system.
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