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A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy?
Most Upvoted Answer
A system expands 5L to 10L against the constant pressure of 2 atm .if ...
DQ= dU+ dW. (or) dQ=dU+P×dV. as W.D is + ve when gas is expanded & -ve when gas is contracted. also heat change is +ve when absorbed & -ve when it release. 1Lit atm=101.3J ...so, 800=dU+2atm×(10-5)L×101.3..... after solving we getdU= - 213 J.
Community Answer
A system expands 5L to 10L against the constant pressure of 2 atm .if ...
Given:
Initial volume (V1) = 5 L
Final volume (V2) = 10 L
Pressure (P) = 2 atm
Heat absorbed (q) = 800 J

To find: Change in internal energy (ΔU)

Explanation:

First, let's calculate the work done by the system during the expansion process using the formula:

W = -PΔV

Where P is the pressure and ΔV is the change in volume.

ΔV = V2 - V1 = 10 L - 5 L = 5 L

W = -2 atm x 5 L = -10 L atm

Since 1 L atm = 101.3 J, we can convert the units:

W = -10 L atm x 101.3 J/L atm = -1013 J

The negative sign indicates that work is done on the system.

Now, let's use the first law of thermodynamics to find the change in internal energy:

ΔU = q - W

Where q is the heat absorbed by the system.

ΔU = 800 J - (-1013 J) = 1813 J

Therefore, the change in internal energy is 1813 J.

Conclusion:

The change in internal energy of the system that expands from 5L to 10L against a constant pressure of 2 atm and absorbs 800 J of heat during the process is 1813 J.
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A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy?
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