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A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy?
Most Upvoted Answer
A system expands 5L to 10L against the constant pressure of 2 atm .if ...
DQ= dU+ dW. (or) dQ=dU+P×dV. as W.D is + ve when gas is expanded & -ve when gas is contracted. also heat change is +ve when absorbed & -ve when it release. 1Lit atm=101.3J ...so, 800=dU+2atm×(10-5)L×101.3..... after solving we getdU= - 213 J.
Community Answer
A system expands 5L to 10L against the constant pressure of 2 atm .if ...
Given:
Initial volume (V1) = 5 L
Final volume (V2) = 10 L
Pressure (P) = 2 atm
Heat absorbed (q) = 800 J
To find: Change in internal energy (ΔU)
Explanation:
First, let's calculate the work done by the system during the expansion process using the formula:
W = -PΔV
Where P is the pressure and ΔV is the change in volume.
ΔV = V2 - V1 = 10 L - 5 L = 5 L
W = -2 atm x 5 L = -10 L atm
Since 1 L atm = 101.3 J, we can convert the units:
W = -10 L atm x 101.3 J/L atm = -1013 J
The negative sign indicates that work is done on the system.
Now, let's use the first law of thermodynamics to find the change in internal energy:
ΔU = q - W
Where q is the heat absorbed by the system.
ΔU = 800 J - (-1013 J) = 1813 J
Therefore, the change in internal energy is 1813 J.
Conclusion:
The change in internal energy of the system that expands from 5L to 10L against a constant pressure of 2 atm and absorbs 800 J of heat during the process is 1813 J.
Initial volume (V1) = 5 L
Final volume (V2) = 10 L
Pressure (P) = 2 atm
Heat absorbed (q) = 800 J
To find: Change in internal energy (ΔU)
Explanation:
First, let's calculate the work done by the system during the expansion process using the formula:
W = -PΔV
Where P is the pressure and ΔV is the change in volume.
ΔV = V2 - V1 = 10 L - 5 L = 5 L
W = -2 atm x 5 L = -10 L atm
Since 1 L atm = 101.3 J, we can convert the units:
W = -10 L atm x 101.3 J/L atm = -1013 J
The negative sign indicates that work is done on the system.
Now, let's use the first law of thermodynamics to find the change in internal energy:
ΔU = q - W
Where q is the heat absorbed by the system.
ΔU = 800 J - (-1013 J) = 1813 J
Therefore, the change in internal energy is 1813 J.
Conclusion:
The change in internal energy of the system that expands from 5L to 10L against a constant pressure of 2 atm and absorbs 800 J of heat during the process is 1813 J.
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A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy?
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A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy?.
A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A system expands 5L to 10L against the constant pressure of 2 atm .if it absorbs 800 j of heat during the process .calculate the value of change in internal energy?.
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