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A rigid body is rotating about an axis. One force F1 acts on the body such that its vector passes through the axis of rotation. Another force F2 acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2 is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1 = 10N & F2= 5N.
- a)0
- b)10.25Nm
- c)0.25Nm
- d)10Nm
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A rigid body is rotating about an axis. One force F1acts on the body s...
The force F1 passes through the axis of rotation, so it will not produce a torque.
The force F2 is perpendicular to axis and radius, so it will provide a torque = r*F2 about the axis of rotation, where ‘r’ is the distance of point of application of force F2 from the axis of rotation.
Therefore, torque = r* F2= 0.05 * 5 Nm
= 0.25Nm.
The force F2 is perpendicular to axis and radius, so it will provide a torque = r*F2 about the axis of rotation, where ‘r’ is the distance of point of application of force F2 from the axis of rotation.
Therefore, torque = r* F2= 0.05 * 5 Nm
= 0.25Nm.
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A rigid body is rotating about an axis. One force F1acts on the body s...
To find the net torque on the body, we need to calculate the torque produced by each force and then add them together.
The torque produced by a force is given by the formula:
τ = r x F
where τ is the torque, r is the radius vector from the axis of rotation to the point of application of the force, and F is the force vector.
For Force F1, since its vector passes through the axis of rotation, the radius vector r is zero. Therefore, the torque produced by F1 is zero.
For Force F2, since it is perpendicular to the axis of rotation and at a point 5cm from the axis, the radius vector r is 5cm. The torque produced by F2 is:
τ2 = r x F2
Since F2 is perpendicular to the radius vector, the cross product of r and F2 is the product of their magnitudes:
τ2 = 5cm * 10N
Converting cm to meters:
τ2 = 0.05m * 10N
τ2 = 0.5Nm
Therefore, the net torque on the body is 0.5Nm.
The torque produced by a force is given by the formula:
τ = r x F
where τ is the torque, r is the radius vector from the axis of rotation to the point of application of the force, and F is the force vector.
For Force F1, since its vector passes through the axis of rotation, the radius vector r is zero. Therefore, the torque produced by F1 is zero.
For Force F2, since it is perpendicular to the axis of rotation and at a point 5cm from the axis, the radius vector r is 5cm. The torque produced by F2 is:
τ2 = r x F2
Since F2 is perpendicular to the radius vector, the cross product of r and F2 is the product of their magnitudes:
τ2 = 5cm * 10N
Converting cm to meters:
τ2 = 0.05m * 10N
τ2 = 0.5Nm
Therefore, the net torque on the body is 0.5Nm.
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A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer?
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A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer?.
A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rigid body is rotating about an axis. One force F1acts on the body such that its vector passes through the axis of rotation. Another force F2acts on it such that it is perpendicular to the axis of rotation and at a point 5cm from the axis. This force F2is perpendicular to the radius vector at its point of application. Find the net torque on the body. Let F1= 10N & F2= 5N.a)0b)10.25Nmc)0.25Nmd)10NmCorrect answer is option 'C'. Can you explain this answer?.
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