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Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s is
- a)82 minutes
- b)50 minutes
- c)28 minutes
- d)37 minutes
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Time required to boil 2 litres of water initially at 20°C by a heater...
Given data:
- Initial temperature of water (T1) = 20°C
- Final temperature of water (T2) = 100°C
- Volume of water = 2 litres = 2 kg
- Efficiency of heater coil = 80%
- Power of heater coil = 500 J/s
Calculating the energy required to heat the water:
- The energy required to raise the temperature of water can be calculated using the formula: Q = mcΔT, where
- m = mass of water = 2 kg
- c = specific heat capacity of water = 4186 J/kg°C
- ΔT = change in temperature = 100°C - 20°C = 80°C
- Substituting the values, we get: Q = 2 * 4186 * 80 = 670880 J
Calculating the actual energy supplied by the heater coil:
- Since the efficiency of the heater coil is 80%, the actual energy supplied can be calculated as: Energy supplied = (100 / 80) * 670880 = 838600 J
Calculating the time required:
- Power = Energy / Time, rearranging the formula we get: Time = Energy / Power
- Substituting the values, we get: Time = 838600 / 500 = 1677.2 seconds = 27.95 minutes
Therefore, the time required to boil 2 litres of water initially at 20°C by a heater coil working at 80% efficiency spending 500 J/s is approximately 28 minutes.
- Initial temperature of water (T1) = 20°C
- Final temperature of water (T2) = 100°C
- Volume of water = 2 litres = 2 kg
- Efficiency of heater coil = 80%
- Power of heater coil = 500 J/s
Calculating the energy required to heat the water:
- The energy required to raise the temperature of water can be calculated using the formula: Q = mcΔT, where
- m = mass of water = 2 kg
- c = specific heat capacity of water = 4186 J/kg°C
- ΔT = change in temperature = 100°C - 20°C = 80°C
- Substituting the values, we get: Q = 2 * 4186 * 80 = 670880 J
Calculating the actual energy supplied by the heater coil:
- Since the efficiency of the heater coil is 80%, the actual energy supplied can be calculated as: Energy supplied = (100 / 80) * 670880 = 838600 J
Calculating the time required:
- Power = Energy / Time, rearranging the formula we get: Time = Energy / Power
- Substituting the values, we get: Time = 838600 / 500 = 1677.2 seconds = 27.95 minutes
Therefore, the time required to boil 2 litres of water initially at 20°C by a heater coil working at 80% efficiency spending 500 J/s is approximately 28 minutes.
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Community Answer
Time required to boil 2 litres of water initially at 20°C by a heater...
Heat required to boil water= mcΔq
= 2 × 4200 × (100-20)
= 6.72 × 103 J
If t be the time of boil then
η × 500 × t = 6.72 × 103
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Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer?
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Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer?.
Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer?.
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