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Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s is
  • a)
    82 minutes
  • b)
    50 minutes
  • c)
    28 minutes
  • d)
    37 minutes
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Time required to boil 2 litres of water initially at 20°C by a heater...
Given data:
- Initial temperature of water (T1) = 20°C
- Final temperature of water (T2) = 100°C
- Volume of water = 2 litres = 2 kg
- Efficiency of heater coil = 80%
- Power of heater coil = 500 J/s

Calculating the energy required to heat the water:
- The energy required to raise the temperature of water can be calculated using the formula: Q = mcΔT, where
- m = mass of water = 2 kg
- c = specific heat capacity of water = 4186 J/kg°C
- ΔT = change in temperature = 100°C - 20°C = 80°C
- Substituting the values, we get: Q = 2 * 4186 * 80 = 670880 J

Calculating the actual energy supplied by the heater coil:
- Since the efficiency of the heater coil is 80%, the actual energy supplied can be calculated as: Energy supplied = (100 / 80) * 670880 = 838600 J

Calculating the time required:
- Power = Energy / Time, rearranging the formula we get: Time = Energy / Power
- Substituting the values, we get: Time = 838600 / 500 = 1677.2 seconds = 27.95 minutes
Therefore, the time required to boil 2 litres of water initially at 20°C by a heater coil working at 80% efficiency spending 500 J/s is approximately 28 minutes.
Free Test
Community Answer
Time required to boil 2 litres of water initially at 20°C by a heater...
Heat required to boil water= mcΔq
= 2 × 4200 × (100-20)
= 6.72 × 103 J
If t be the time of boil then
η × 500 × t = 6.72 × 103
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Time required to boil 2 litres of water initially at 20°C by a heater coil which works at 80% efficiency spending 500 joule/s isa)82 minutesb)50 minutesc)28 minutesd)37 minutesCorrect answer is option 'C'. Can you explain this answer?
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