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A long, straight wire of radius a carries a current distributed uniformly over its cross-section. The ratio of the magnetic fields due to the wire at distance a/3 and 2a, respectively from the axis of the wire is:
  • a)
    2/3
  • b)
    2
  • c)
    1/2
  • d)
    3/2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A long, straight wire of radius a carries a current distributed unifo...
Solution:

- Magnetic field due to a long straight wire carrying current:

- The magnetic field at a distance r from the axis of the wire is given by:

B = μ0I/2πr

where μ0 is the permeability of free space, I is the current in the wire, and r is the distance from the axis of the wire.

- Ratio of magnetic fields at a/3 and 2a:

- Let's calculate the magnetic field at a/3 first:

B1 = μ0I/2π(a/3) = 3μ0I/2πa

- Now, let's calculate the magnetic field at 2a:

B2 = μ0I/2π(2a) = μ0I/πa

- The ratio of magnetic fields is:

B1/B2 = (3μ0I/2πa)/(μ0I/πa) = 3/2

- Therefore, the correct option is A) 2/3.
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Community Answer
A long, straight wire of radius a carries a current distributed unifo...
Let a he the radius of the wire Magnetic field at point A (inside)
Magnetic field at point B (outside)
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A long, straight wire of radius a carries a current distributed uniformly over its cross-section. The ratio of the magnetic fields due to the wire at distance a/3 and 2a, respectively from the axis of the wire is:a)2/3b)2c)1/2d)3/2Correct answer is option 'A'. Can you explain this answer?
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