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It takes 10s and 15s, respectively, for two trains travelling at different constant speeds to completely pass a telegraph post. The length of the first train is 120 m and that of the second train is 150 m. The magnitude of the difference in the speeds of the two trains (in m/s) is _____.
  • a)
    2.0
  • b)
    10.0
  • c)
    12.0
  • d)
    22.0
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
It takes 10s and 15s, respectively, for two trains travelling at diffe...
To solve this problem, we can use the formula:

Speed = Distance / Time

Given:
Length of first train (L1) = 120 m
Length of second train (L2) = 150 m
Time taken by first train to pass the telegraph post (T1) = 10 s
Time taken by second train to pass the telegraph post (T2) = 15 s

Let's calculate the speeds of the two trains first.

Speed of first train (S1) = L1 / T1 = 120 / 10 = 12 m/s
Speed of second train (S2) = L2 / T2 = 150 / 15 = 10 m/s

Now, let's calculate the magnitude of the difference in speeds.

Magnitude of the difference in speeds = |S1 - S2|

Substituting the values, we get:
Magnitude of the difference in speeds = |12 - 10| = 2 m/s

Therefore, the correct answer is option A) 2.0.
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Community Answer
It takes 10s and 15s, respectively, for two trains travelling at diffe...
Speed = length / time
⇒ length = speed x time
120 = 10 x s1 ⇒ s= 12
150 = 15 x s⇒ s2 = 10
|s1 - s2| = 2
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It takes 10s and 15s, respectively, for two trains travelling at different constant speeds to completely pass a telegraph post. The length of the first train is 120 m and that of the second train is 150 m. The magnitude of the difference in the speeds of the two trains (in m/s) is _____.a)2.0b)10.0c)12.0d)22.0Correct answer is option 'A'. Can you explain this answer?
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