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A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps per minute to the deer’s 4. If the tiger and the deer cover 8 meters and 5 meters per leap respectively. What distance in metres will be tiger have to run before it catches the deer?
  • a)
    568
  • b)
    800
  • c)
    400
  • d)
    200
Correct answer is option 'B'. Can you explain this answer?
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A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps ...
If the tiger takes 5 leaps per minute towards the deer, it will take 50/5 = <50 =10="">>10 minutes for the tiger to catch up to the deer.
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A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps ...
From The Question
A tiger is 50 leaps of its own from a deer.
Tiger takes 5 leaps per minute.
Deer takes 4 leaps per minute.
Tiger covers 8 meters per leap.
Deer covers 5 meters per leap.
Therefore, the tiger covers 5 x 8 = 40 meters/minute.
The deer covers 4 x 5 = 20 meters/minute.
Hence, the relative speed is 20 meters/minute.
The tiger is behind the deer by 50 x 8 = 400 meters.
Therefore, the time taken = distance/speed = 400/20 = 20 minutes.
Therefore, in the 20 minutes, the tiger will cover 20 x 40 = 800 meters.
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A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps per minute to the deer’s 4. If the tiger and the deer cover 8 meters and 5 meters per leap respectively. What distance in metres will be tiger have to run before it catches the deer?a)568b)800c)400d)200Correct answer is option 'B'. Can you explain this answer?
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