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A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point?
Most Upvoted Answer
A particle is fired with velocity u making theta angle with the horizo...
Change in Velocity at Highest Point
When a particle is fired with velocity u making theta angle with the horizontal, the velocity of the particle changes as it moves through its trajectory. At the highest point of its trajectory, the particle experiences a change in velocity.
Explanation
- When the particle is fired with velocity u, it has an initial velocity in the horizontal and vertical direction.
- As the particle moves through its trajectory, it experiences a change in velocity due to the gravitational force acting on it.
- At the highest point of its trajectory, the particle stops momentarily before changing its direction of motion.
- At this point, the velocity of the particle is purely horizontal, and the vertical velocity component is zero.
- The change in velocity at the highest point is equal to the initial vertical velocity component of the particle.
- The magnitude of the change in velocity is equal to the initial vertical velocity component multiplied by -1.
Formula
The change in velocity at the highest point can be calculated using the following formula:
Change in Velocity = -u sin(theta)
Conclusion
Therefore, when a particle is fired with velocity u making theta angle with the horizontal, the change in velocity at the highest point is equal to the initial vertical velocity component of the particle, and can be calculated using the formula -u sin(theta).
Community Answer
A particle is fired with velocity u making theta angle with the horizo...
At the time of projection, the particle's speed is u and the particle's speed at the highest point the particle's speed is ucosθ. So, the change in speed is,
Δu=u−ucosθ
Now, the initial velocity is,
u
=ucosθ
i
^
+usinθ
j
^
and the final velocity (at highest point) is,
v
=ucosθ
i
^
Therefore, the change in velocity is,
Δ
v
=
u
−
v
=ucosθ
i
^
+usinθ
j
^
−ucosθ
i
^
=usinθ
j
^
⇒∣Δ
v
∣=usinθ
Δu=u−ucosθ
Now, the initial velocity is,
u
=ucosθ
i
^
+usinθ
j
^
and the final velocity (at highest point) is,
v
=ucosθ
i
^
Therefore, the change in velocity is,
Δ
v
=
u
−
v
=ucosθ
i
^
+usinθ
j
^
−ucosθ
i
^
=usinθ
j
^
⇒∣Δ
v
∣=usinθ
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A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point?
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A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point?.
A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is fired with velocity u making theta angle with the horizontal. What is the change in velocity when it is at the highest point?.
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