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The binding energy per nucleon in deuterium and helium nuclei are 1.1MeV & 7.0MeV respectively when two deuterium nuclei fuse to form a helium nucleus the energy released in fusion is ? explained ans i need
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The binding energy per nucleon in deuterium and helium nuclei are 1.1M...
The binding energy per nucleon in deuterium (D) and helium (He) nuclei is given as 1.1 MeV.

This means that on average, each nucleon (proton or neutron) in a deuterium or helium nucleus is bound to the nucleus with an energy of 1.1 MeV.

To calculate the total binding energy of a nucleus, we multiply the binding energy per nucleon by the total number of nucleons in the nucleus.

Deuterium (D) nucleus consists of one proton and one neutron, so the total binding energy of a deuterium nucleus would be:

Total binding energy of D = Binding energy per nucleon * Number of nucleons
= 1.1 MeV * 2
= 2.2 MeV

Helium (He) nucleus consists of two protons and two neutrons, so the total binding energy of a helium nucleus would be:

Total binding energy of He = Binding energy per nucleon * Number of nucleons
= 1.1 MeV * 4
= 4.4 MeV

Therefore, the total binding energy of a deuterium nucleus is 2.2 MeV and the total binding energy of a helium nucleus is 4.4 MeV.
Community Answer
The binding energy per nucleon in deuterium and helium nuclei are 1.1M...
(7×4)-(2×1.1)=25.8MeV
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The binding energy per nucleon in deuterium and helium nuclei are 1.1MeV & 7.0MeV respectively when two deuterium nuclei fuse to form a helium nucleus the energy released in fusion is ? explained ans i need
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