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Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)
- a)1100
- b)0011
- c)0000
- d)1111
Correct answer is option 'C'. Can you explain this answer?
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Assume that a 4-bit serial in/serial out shift register is initially c...
Problem:
Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)
Solution:
To solve this problem, let's go step by step:
Step 1: Clearing the shift register
- The shift register is initially clear, which means all bits are set to 0.
Step 2: Storing the nibble 1100
- The nibble 1100 is stored in the shift register serially, starting from the right-most bit.
- The first clock pulse will shift the first bit (1) into the shift register.
- After the first clock pulse, the shift register will contain the pattern 0001.
Step 3: Second clock pulse
- The second clock pulse will shift the second bit (1) into the shift register.
- After the second clock pulse, the shift register will contain the pattern 0011.
Therefore, the 4-bit pattern after the second clock pulse is 0011 (right-most bit first), which corresponds to option 'c'.
Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)
Solution:
To solve this problem, let's go step by step:
Step 1: Clearing the shift register
- The shift register is initially clear, which means all bits are set to 0.
Step 2: Storing the nibble 1100
- The nibble 1100 is stored in the shift register serially, starting from the right-most bit.
- The first clock pulse will shift the first bit (1) into the shift register.
- After the first clock pulse, the shift register will contain the pattern 0001.
Step 3: Second clock pulse
- The second clock pulse will shift the second bit (1) into the shift register.
- After the second clock pulse, the shift register will contain the pattern 0011.
Therefore, the 4-bit pattern after the second clock pulse is 0011 (right-most bit first), which corresponds to option 'c'.
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Community Answer
Assume that a 4-bit serial in/serial out shift register is initially c...
In Serial-In/Serial-Out shift register, data will be shifted one at a time with every clock pulse. Therefore,
Wait | Store
1100 | 0000
110 | 0000 1st clock
11 | 0000 2nd clock.
Wait | Store
1100 | 0000
110 | 0000 1st clock
11 | 0000 2nd clock.
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Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)a)1100b)0011c)0000d)1111Correct answer is option 'C'. Can you explain this answer?
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