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A bidirectional 4-bit shift register is storing the nibble 1101. Its  input is high. The nibble 1011 is waiting to be entered on the serial data-input line. After these clock pulses, the shift register is storing (in binary system) _________________
    Correct answer is '0111'. Can you explain this answer?
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    A bidirectional 4-bit shift register is storing the nibble 1101. Its i...
    First given number is 1101
    the number is shifted right/left bar
    it means that the left most number will move right
    so 1101 left most 1 will move right side and become 1011 then again it will shift right and become 0111
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    A bidirectional 4-bit shift register is storing the nibble 1101. Its i...
    0111
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    A bidirectional 4-bit shift register is storing the nibble 1101. Its input is high. The nibble 1011 is waiting to be entered on the serial data-input line. After these clock pulses, the shift register is storing (in binary system) _________________Correct answer is '0111'. Can you explain this answer?
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    A bidirectional 4-bit shift register is storing the nibble 1101. Its input is high. The nibble 1011 is waiting to be entered on the serial data-input line. After these clock pulses, the shift register is storing (in binary system) _________________Correct answer is '0111'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A bidirectional 4-bit shift register is storing the nibble 1101. Its input is high. The nibble 1011 is waiting to be entered on the serial data-input line. After these clock pulses, the shift register is storing (in binary system) _________________Correct answer is '0111'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bidirectional 4-bit shift register is storing the nibble 1101. Its input is high. The nibble 1011 is waiting to be entered on the serial data-input line. After these clock pulses, the shift register is storing (in binary system) _________________Correct answer is '0111'. Can you explain this answer?.
    Solutions for A bidirectional 4-bit shift register is storing the nibble 1101. Its input is high. The nibble 1011 is waiting to be entered on the serial data-input line. After these clock pulses, the shift register is storing (in binary system) _________________Correct answer is '0111'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
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