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A 2-wire d.c. distributor 200 meters long is uniformly loaded with 2A/meter resistance of a single wire is 0.3 Ω/km. If the distributor is fed at one end, calculate the maximum voltage drop
  • a)
    10 volt
  • b)
    12 volt
  • c)
    24 volt
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A 2-wire d.c. distributor 200 meters long is uniformly loaded with 2A/...
To find the total resistance of the 2-wire d.c. distributor, we need to first calculate the resistance of each wire and then multiply it by the length of the distributor.

The resistance of a single wire is given as 0.3 ohms/meter.

Since there are 2 wires, the total resistance of each wire is 0.3 ohms/meter * 200 meters = 60 ohms.

Therefore, the total resistance of the 2-wire d.c. distributor is 2 * 60 ohms = 120 ohms.
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Community Answer
A 2-wire d.c. distributor 200 meters long is uniformly loaded with 2A/...
Concept:
In a uniformly loaded distributor fed at one end, the maximum total voltage drop = IR/2
In a uniformly loaded distributor fed at both ends, the maximum total voltage drop = IR/8
The maximum voltage drop in the case of uniformly loaded distributor fed at both ends is one-fourth of the maximum voltage drop in the case of uniformly loaded distributor fed at one end.
Calculation:
Length of distributor = 200 m = 0.2 km
Current supplied by distributor = 2 amperes/meter
Total current supplied by distributor (I) = 200 × 2 = 400 A
The resistance of single wire = 0.3 Ω/km
Total resistance = 0.3 × 0.2 = 0.06 Ω
Maximum voltage drop
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A 2-wire d.c. distributor 200 meters long is uniformly loaded with 2A/meter resistance of a single wire is 0.3 Ω/km. If the distributor is fed at one end, calculate the maximum voltage dropa)10 voltb)12 voltc)24 voltd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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