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A 2-wire DC distributor cable 800 m long is loaded with 1 A/m. Resistance of each conductor is 0.05 Ω/km. Calculate the maximum voltage drop if the distributor is fed from both ends with equal voltages of 220 V.
  • a)
    2 V
  • b)
    8 V
  • c)
    16 V
  • d)
    4 V
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A 2-wire DC distributor cable 800 m long is loaded with 1 A/m. Resista...
Concept: 
Total current supplied by the distributor, I = 800 × 1 = 800A
Total resistance of the distributor , R = 2 × 0.05 × 0.8 = 0.08 ohm
For a uniformly loaded DC-distributed wire fed from both sides with equal voltages, the Vmin occurs at mid-point( x = l/2).
So the maximum voltage drop is at the mid-point:
Calculation:
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Community Answer
A 2-wire DC distributor cable 800 m long is loaded with 1 A/m. Resista...
To calculate the maximum voltage drop in the 2-wire DC distributor cable, we need to consider the resistance of the cable and the current flowing through it.

Given:
Length of the cable (L) = 800 m
Current per unit length (I) = 1 A/m
Resistance per unit length (R) = 0.05 Ω/km
Voltage at each end of the cable (V) = 220 V

1. Calculate the total resistance of the cable:
The resistance of the cable can be calculated using the formula:
Resistance (R) = Resistance per unit length (R') * Length of the cable (L)

In this case, R' = 0.05 Ω/km and L = 800 m.
So, R = 0.05 Ω/km * 800 m = 40 Ω

2. Calculate the total current flowing through the cable:
The total current flowing through the cable can be calculated using the formula:
Total current (I_total) = Current per unit length (I) * Length of the cable (L)

In this case, I = 1 A/m and L = 800 m.
So, I_total = 1 A/m * 800 m = 800 A

3. Calculate the voltage drop across the cable:
The voltage drop across the cable can be calculated using Ohm's Law:
Voltage drop (V_drop) = Resistance (R) * Total current (I_total)

In this case, R = 40 Ω and I_total = 800 A.
So, V_drop = 40 Ω * 800 A = 32000 V

4. Determine the maximum voltage drop:
Since the cable is fed from both ends with equal voltages, the maximum voltage drop will occur when the cable is fully loaded. In this case, the maximum voltage drop will be half of the total voltage drop.

Maximum voltage drop = V_drop / 2 = 32000 V / 2 = 16000 V

Therefore, the maximum voltage drop in the 2-wire DC distributor cable is 16000 V.

The correct answer is option C) 16 V.
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it depends on the length of the conductor the capacitance of the line is proportional to the length of the transmission line their effect is negligible on the performance of short having a length less than 80 km and low voltage transmission accidents of the transmission line along with the conductances forms the shunted mittens the conductance and the transmission line is because of the leakage over the surface of the conductor considered a line consisting of two conductors and be each of radius are the distance between the conductors being Des shown in the diagram below minus the potential difference between the conductors and via's work QA charge on conductor QB charge on conductor vvab pencil difference between conductor and the Epsilon minus absolute primitivity QA plus QV = 0 so that QA equals QB - equals DBA equals data equals DB equals our substituting these values and voltage equation we get the capacitance between the conductors is cab is referred to as lying to line capacitance if the two conductors are in VR oppositely charge then the potential difference between them is zero then the potential of each conductor is given by one half bath the capacitance between each conductor and point of zero potential and is capacitive CN is called the capacitance to neut or capacitance to ground capacitance cab is the combination of two equal capacity and VN series thus capacitance to neutral is twice the capacitance between the conductors IE CN equals to Cave the absolute primitivity Epsilon is given by Epsilon equals epsilono Epsilon are where epsilano is the permittivity of the free space and Epsilon or is the relative primitivity of the medium prayer capacitance reactants between one conductor and neutral capacitance of the symmetrical three phase line let a balanced system of voltage be applied to a symmetrical three-phase line shown below the phasor diagram of the three phase line with equilateral spacing is shown below take the voltage of conductor to neutral as a reference phaser the potential difference between conductor and we can be written the similarly potential difference between conductors and sea is on adding equations one and two we get also combining equation three and four from equation 6 and 7 the line to neutral capacitance the capacitance of symmetrical three phase line is same as that of the two wire line Related: Capacitance of Transmission Lines?

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A 2-wire DC distributor cable 800 m long is loaded with 1 A/m. Resistance of each conductor is 0.05 /km. Calculate the maximum voltage drop if the distributor is fed from both ends with equal voltages of 220 V.a)2 Vb)8 Vc)16 Vd)4 VCorrect answer is option 'B'. Can you explain this answer?
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