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In D flip-flop, if clock input is LOW, the D input ___________
- a)Has no effect
- b)Goes high
- c)Goes low
- d)Has effect
Correct answer is option 'A'. Can you explain this answer?
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In D flip-flop, if clock input is LOW, the D input ___________a)Has no...
In D flip-flop, if clock input is LOW, the D input has no effect, since the set and reset inputs of the NAND flip-flop are kept HIGH.
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In D flip-flop, if clock input is LOW, the D input ___________a)Has no...
Effect of Clock Input on D Flip-Flop:
When the clock input of a D flip-flop is LOW, the D input has no effect on the output of the flip-flop. This is because the D flip-flop is designed to only change its output state when the clock input transitions from LOW to HIGH (rising edge trigger) or from HIGH to LOW (falling edge trigger).
Explanation:
- Clock Input: The clock input is used to synchronize the data input (D) with the timing of the flip-flop. When the clock input is LOW, the flip-flop is not triggered to change its state based on the D input.
- Operation: In a D flip-flop, the output state is determined by the D input value at the rising or falling edge of the clock signal. If the clock input is LOW, the flip-flop remains in its current state regardless of the D input.
- No Change: Since the clock input is not transitioning from LOW to HIGH or vice versa, the flip-flop does not respond to any changes in the D input. Therefore, the D input has no effect on the output of the flip-flop when the clock input is LOW.
- Functionality: This behavior ensures that the D flip-flop only captures and stores the input data when the clock signal changes state, allowing for controlled and synchronized operation in digital circuits.
In conclusion, when the clock input of a D flip-flop is LOW, the D input has no effect on the output state of the flip-flop. It is essential to understand the timing requirements and behavior of flip-flops in digital circuit design to ensure proper functionality and reliable operation.
When the clock input of a D flip-flop is LOW, the D input has no effect on the output of the flip-flop. This is because the D flip-flop is designed to only change its output state when the clock input transitions from LOW to HIGH (rising edge trigger) or from HIGH to LOW (falling edge trigger).
Explanation:
- Clock Input: The clock input is used to synchronize the data input (D) with the timing of the flip-flop. When the clock input is LOW, the flip-flop is not triggered to change its state based on the D input.
- Operation: In a D flip-flop, the output state is determined by the D input value at the rising or falling edge of the clock signal. If the clock input is LOW, the flip-flop remains in its current state regardless of the D input.
- No Change: Since the clock input is not transitioning from LOW to HIGH or vice versa, the flip-flop does not respond to any changes in the D input. Therefore, the D input has no effect on the output of the flip-flop when the clock input is LOW.
- Functionality: This behavior ensures that the D flip-flop only captures and stores the input data when the clock signal changes state, allowing for controlled and synchronized operation in digital circuits.
In conclusion, when the clock input of a D flip-flop is LOW, the D input has no effect on the output state of the flip-flop. It is essential to understand the timing requirements and behavior of flip-flops in digital circuit design to ensure proper functionality and reliable operation.
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In D flip-flop, if clock input is LOW, the D input ___________a)Has no effectb)Goes highc)Goes lowd)Has effectCorrect answer is option 'A'. Can you explain this answer?
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