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A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.
- a)6
- b)4.95
- c)5.7
- d)5.5
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A non-pipeline system takes 50ns to process a task. The same task can ...
Data:
Time for non-pipelined execution per task = tn = 50 ns
Time for pipelined execution per task = tp = 10 ns
Number of stages in the pipeline = k = 6
Number of tasks = 500
Formula
S = speed up factor
Time for non-pipelined execution per task = tn = 50 ns
Time for pipelined execution per task = tp = 10 ns
Number of stages in the pipeline = k = 6
Number of tasks = 500
Formula
S = speed up factor
Calculation:
Time for non-pipelined = Tn = tn x Number of tasks
Time for non-pipelined = Tn = 50 x 500
Time for pipelined = Tp = 1st task x k x tp + (All Remaining Tasks (k - 1)) x tp
Time for pipelined = Tp = 1 x 6 x 10 + (500 - 1) x 10
Time for non-pipelined = Tn = tn x Number of tasks
Time for non-pipelined = Tn = 50 x 500
Time for pipelined = Tp = 1st task x k x tp + (All Remaining Tasks (k - 1)) x tp
Time for pipelined = Tp = 1 x 6 x 10 + (500 - 1) x 10
Most Upvoted Answer
A non-pipeline system takes 50ns to process a task. The same task can ...
Data:
Time for non-pipelined execution per task = tn = 50 ns
Time for pipelined execution per task = tp = 10 ns
Number of stages in the pipeline = k = 6
Number of tasks = 500
Formula
S = speed up factor
Time for non-pipelined execution per task = tn = 50 ns
Time for pipelined execution per task = tp = 10 ns
Number of stages in the pipeline = k = 6
Number of tasks = 500
Formula
S = speed up factor
Calculation:
Time for non-pipelined = Tn = tn x Number of tasks
Time for non-pipelined = Tn = 50 x 500
Time for pipelined = Tp = 1st task x k x tp + (All Remaining Tasks (k - 1)) x tp
Time for pipelined = Tp = 1 x 6 x 10 + (500 - 1) x 10
Time for non-pipelined = Tn = tn x Number of tasks
Time for non-pipelined = Tn = 50 x 500
Time for pipelined = Tp = 1st task x k x tp + (All Remaining Tasks (k - 1)) x tp
Time for pipelined = Tp = 1 x 6 x 10 + (500 - 1) x 10
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Community Answer
A non-pipeline system takes 50ns to process a task. The same task can ...
Given information:
- Non-pipeline system takes 50ns to process a task.
- Six-segment pipeline with a clock cycle of 10ns can process the same task.
Calculating the time taken by the non-pipeline system:
- For 500 tasks, the total time taken by the non-pipeline system can be calculated as:
Total time = Time per task * Number of tasks
= 50ns * 500
= 25000ns
Calculating the time taken by the pipeline system:
- In a pipeline system, the tasks are divided into segments that can be processed simultaneously.
- Each segment takes 10ns to complete.
- However, there is an additional overhead of pipeline latency.
- For a six-segment pipeline, the pipeline latency can be calculated as:
Pipeline latency = (Number of segments - 1) * Clock cycle
= (6 - 1) * 10ns
= 50ns
- Therefore, the effective time taken by the pipeline system to process a task is:
Effective time per task = Pipeline latency + Time per segment
= 50ns + (10ns * 6)
= 110ns
- For 500 tasks, the total time taken by the pipeline system can be calculated as:
Total time = Effective time per task * Number of tasks
= 110ns * 500
= 55000ns
Calculating the speedup ratio:
- The speedup ratio can be calculated as the ratio of the time taken by the non-pipeline system to the time taken by the pipeline system.
- Speedup ratio = Time taken by non-pipeline system / Time taken by pipeline system
= 25000ns / 55000ns
= 0.4545
- Approximating the speedup ratio to two decimal places, we get 0.45.
- Converting this to a percentage, we get approximately 45%.
- Therefore, the speedup ratio of the pipeline system for 500 tasks is approximately 4.95 (option B).
- Non-pipeline system takes 50ns to process a task.
- Six-segment pipeline with a clock cycle of 10ns can process the same task.
Calculating the time taken by the non-pipeline system:
- For 500 tasks, the total time taken by the non-pipeline system can be calculated as:
Total time = Time per task * Number of tasks
= 50ns * 500
= 25000ns
Calculating the time taken by the pipeline system:
- In a pipeline system, the tasks are divided into segments that can be processed simultaneously.
- Each segment takes 10ns to complete.
- However, there is an additional overhead of pipeline latency.
- For a six-segment pipeline, the pipeline latency can be calculated as:
Pipeline latency = (Number of segments - 1) * Clock cycle
= (6 - 1) * 10ns
= 50ns
- Therefore, the effective time taken by the pipeline system to process a task is:
Effective time per task = Pipeline latency + Time per segment
= 50ns + (10ns * 6)
= 110ns
- For 500 tasks, the total time taken by the pipeline system can be calculated as:
Total time = Effective time per task * Number of tasks
= 110ns * 500
= 55000ns
Calculating the speedup ratio:
- The speedup ratio can be calculated as the ratio of the time taken by the non-pipeline system to the time taken by the pipeline system.
- Speedup ratio = Time taken by non-pipeline system / Time taken by pipeline system
= 25000ns / 55000ns
= 0.4545
- Approximating the speedup ratio to two decimal places, we get 0.45.
- Converting this to a percentage, we get approximately 45%.
- Therefore, the speedup ratio of the pipeline system for 500 tasks is approximately 4.95 (option B).
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Question Description
A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.a)6b)4.95c)5.7d)5.5Correct answer is option 'B'. Can you explain this answer? for GATE 2025 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.a)6b)4.95c)5.7d)5.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.a)6b)4.95c)5.7d)5.5Correct answer is option 'B'. Can you explain this answer?.
A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.a)6b)4.95c)5.7d)5.5Correct answer is option 'B'. Can you explain this answer? for GATE 2025 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.a)6b)4.95c)5.7d)5.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A non-pipeline system takes 50ns to process a task. The same task can be processed in six-segment pipeline with a clockcycle of 10ns. Determine approximately the speedup ratio of the pipeline for 500 tasks.a)6b)4.95c)5.7d)5.5Correct answer is option 'B'. Can you explain this answer?.
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