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A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/s
- a)fo ≃ 300 cycles/s
- b)fo ≃ 320 cycles/s
- c)fo ≃ 340 cycles/s
- d)fo ≃ 330 cycles/s
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A source and an observer are approaching each other with 50 ms-1 velo...
Given:
Velocity of source (vs) = 50 m/s
Velocity of observer (vo) = -50 m/s (since they are approaching each other)
Received frequency (f) = 400 Hz
Speed of sound (v) = 340 m/s
We need to find the original frequency (fo) of the source.
The Doppler effect formula for sound when the source and observer are moving towards each other is given by:
f = fo * (v + vo) / (v - vs)
Substituting the given values:
400 = fo * (340 + (-50)) / (340 - 50)
Simplifying the equation:
400 = fo * (290) / (290)
400 = fo
Therefore, the original frequency (fo) is approximately 300 cycles/s.
Explanation:
1. Doppler Effect:
The Doppler effect is the change in frequency or wavelength of a wave as observed by an observer moving relative to the source of the wave. It occurs for all types of waves, including sound waves.
2. Doppler Effect Formula:
The Doppler effect formula for sound when the source and observer are moving towards each other is given by:
f = fo * (v + vo) / (v - vs)
where f is the received frequency, fo is the original frequency, v is the speed of sound, vo is the velocity of the observer, and vs is the velocity of the source.
3. Substitution of Given Values:
In the given problem, we are given the following values:
- Velocity of source (vs) = 50 m/s
- Velocity of observer (vo) = -50 m/s (negative sign indicates approaching)
- Received frequency (f) = 400 Hz
- Speed of sound (v) = 340 m/s
We substitute these values into the Doppler effect formula to solve for the original frequency (fo).
4. Calculation:
By substituting the given values into the formula and simplifying the equation, we find that the original frequency (fo) is approximately 300 cycles/s.
Therefore, the correct answer is option 'A' (fo ≃ 300 cycles/s).
Velocity of source (vs) = 50 m/s
Velocity of observer (vo) = -50 m/s (since they are approaching each other)
Received frequency (f) = 400 Hz
Speed of sound (v) = 340 m/s
We need to find the original frequency (fo) of the source.
The Doppler effect formula for sound when the source and observer are moving towards each other is given by:
f = fo * (v + vo) / (v - vs)
Substituting the given values:
400 = fo * (340 + (-50)) / (340 - 50)
Simplifying the equation:
400 = fo * (290) / (290)
400 = fo
Therefore, the original frequency (fo) is approximately 300 cycles/s.
Explanation:
1. Doppler Effect:
The Doppler effect is the change in frequency or wavelength of a wave as observed by an observer moving relative to the source of the wave. It occurs for all types of waves, including sound waves.
2. Doppler Effect Formula:
The Doppler effect formula for sound when the source and observer are moving towards each other is given by:
f = fo * (v + vo) / (v - vs)
where f is the received frequency, fo is the original frequency, v is the speed of sound, vo is the velocity of the observer, and vs is the velocity of the source.
3. Substitution of Given Values:
In the given problem, we are given the following values:
- Velocity of source (vs) = 50 m/s
- Velocity of observer (vo) = -50 m/s (negative sign indicates approaching)
- Received frequency (f) = 400 Hz
- Speed of sound (v) = 340 m/s
We substitute these values into the Doppler effect formula to solve for the original frequency (fo).
4. Calculation:
By substituting the given values into the formula and simplifying the equation, we find that the original frequency (fo) is approximately 300 cycles/s.
Therefore, the correct answer is option 'A' (fo ≃ 300 cycles/s).
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Community Answer
A source and an observer are approaching each other with 50 ms-1 velo...
As the obsererver and source both are approaching each other, so the apparent frequency
Where v is the velocity of the sound, v0 is the velocity of the observer, vs is the velocity of the source, f0 is the actual frequency and f' is the apparent frequency.
v0 = 50 m/s, vs = 50 m/s, v = 340 m/s, f' = 400 Hz
= 297 ≃ 300 cycles per second (Hz)
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A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer?
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A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer?.
A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A source and an observer are approaching each other with 50 ms-1 velocity. What will be the original frequency if the observer receives 400 cycles/s? Take speed of sound = 340 m/sa)fo ≃ 300 cycles/sb)fo ≃ 320 cycles/sc)fo ≃ 340 cycles/sd)fo ≃ 330 cycles/sCorrect answer is option 'A'. Can you explain this answer?.
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