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Ratio of intensities of coherent waves in YDSE is 9 : 4. Ratio of intensities of minima to the maxima produced is
  • a)
    2 : 3
  • b)
    4 : 9
  • c)
    1 : 16
  • d)
    1 : 25
Correct answer is option 'D'. Can you explain this answer?
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Ratio of intensities of coherent waves in YDSE is 9 : 4. Ratio of int...
= 1 : 25
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Ratio of intensities of coherent waves in YDSE is 9 : 4. Ratio of int...
Ratio of Intensities in YDSE
In Young's Double Slit Experiment (YDSE), the ratio of intensities of coherent waves is given as 9 : 4. This means that the square of the amplitudes of the two waves is in the ratio 9 : 4.

Ratio of Minima to Maxima Intensities
The ratio of intensities of minima to the maxima can be calculated using the formula:
$$
\frac{I_{min}}{I_{max}} = \frac{0}{4} = 0
$$
This means that the intensity at the minima is zero compared to the intensity at the maxima. Therefore, the ratio of intensities of minima to the maxima is 0 : 1.

Final Ratio
To find the ratio of intensities of minima to maxima in terms of the given ratio of coherent waves intensities (9 : 4), we square the given ratio:
$$(9^2) : (4^2) = 81 : 16$$
Simplifying the ratio further, we get:
$$81 : 16 = 1 : 5^2 = 1 : 25$$
Therefore, the correct answer is option 'D' - 1 : 25.
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Ratio of intensities of coherent waves in YDSE is 9 : 4. Ratio of intensities of minima to the maxima produced isa)2 : 3b)4 : 9c)1 : 16d)1 : 25Correct answer is option 'D'. Can you explain this answer?
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