NEET Exam > NEET Questions > The focal length of the eyepiece and the obje...
Start Learning for Free
The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)?
Most Upvoted Answer
The focal length of the eyepiece and the objective of an astronomical ...
Given:
- Focal length of eyepiece (fe) = 4 cm
- Focal length of objective (fo) = 50 cm
- Least distance of distinct vision (D) = 25 cm
To find:
- Length of the telescope for the adjustment in which eye is most strained
Solution:
1. Magnifying power of the telescope (M):
The magnifying power of a telescope is given by the formula:
M = - (fo/fe)
Substituting the given values, we get:
M = - (50/4)
M = -12.5
The negative sign indicates that the image formed by the telescope is inverted.
2. Total magnification (Mtotal):
The total magnification of a telescope is given by the formula:
Mtotal = M * (1 + D/fe)
Substituting the given values, we get:
Mtotal = -12.5 * (1 + 25/4)
Mtotal = -12.5 * (1 + 6.25)
Mtotal = -12.5 * 7.25
Mtotal = -90.625
3. Length of the telescope (L):
The length of the telescope is given by the formula:
L = (fo + fe) * (1 + Mtotal)
Substituting the given values, we get:
L = (50 + 4) * (1 + (-90.625))
L = 54 * (-89.625)
L ≈ -4846.25 cm
Since the length of the telescope cannot be negative, we take the absolute value:
L ≈ 4846.25 cm
Therefore, the length of the telescope for the adjustment in which the eye is most strained is approximately 4846.25 cm.
Conclusion:
The length of the telescope for the adjustment in which the eye is most strained is approximately 4846.25 cm.
- Focal length of eyepiece (fe) = 4 cm
- Focal length of objective (fo) = 50 cm
- Least distance of distinct vision (D) = 25 cm
To find:
- Length of the telescope for the adjustment in which eye is most strained
Solution:
1. Magnifying power of the telescope (M):
The magnifying power of a telescope is given by the formula:
M = - (fo/fe)
Substituting the given values, we get:
M = - (50/4)
M = -12.5
The negative sign indicates that the image formed by the telescope is inverted.
2. Total magnification (Mtotal):
The total magnification of a telescope is given by the formula:
Mtotal = M * (1 + D/fe)
Substituting the given values, we get:
Mtotal = -12.5 * (1 + 25/4)
Mtotal = -12.5 * (1 + 6.25)
Mtotal = -12.5 * 7.25
Mtotal = -90.625
3. Length of the telescope (L):
The length of the telescope is given by the formula:
L = (fo + fe) * (1 + Mtotal)
Substituting the given values, we get:
L = (50 + 4) * (1 + (-90.625))
L = 54 * (-89.625)
L ≈ -4846.25 cm
Since the length of the telescope cannot be negative, we take the absolute value:
L ≈ 4846.25 cm
Therefore, the length of the telescope for the adjustment in which the eye is most strained is approximately 4846.25 cm.
Conclusion:
The length of the telescope for the adjustment in which the eye is most strained is approximately 4846.25 cm.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)?
Question Description
The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)?.
The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)?.
Solutions for The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? defined & explained in the simplest way possible. Besides giving the explanation of
The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)?, a detailed solution for The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? has been provided alongside types of The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? theory, EduRev gives you an
ample number of questions to practice The focal length of the eyepiece and the objective of an astronomical telescope are 4cm and 50cm . The length of the telescope for the adjustment in which eye is most stained will be about (least distance of distinct vision is 25 cm)? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup