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The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be?
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The magnification of a compound microscope is the final image at the l...
The magnification of a compound microscope is determined by the combination of the magnification of the objective lens and the eyepiece. To find the value of the focal length of the eyepiece, we can use the magnification formula:
Magnification = Magnification of Objective Lens × Magnification of Eyepiece
Given that the magnification of the objective lens is 15 and the final image is formed at the least distance of distinct vision, which is 25 cm or 0.25 m, we can calculate the magnification of the eyepiece.
Let's assume the focal length of the eyepiece is f. Now, we can calculate the magnification of the eyepiece using the formula:
Magnification of Eyepiece = 1 + (Distance of Final Image / Focal Length of Eyepiece)
Substituting the given values, we have:
90 = 15 × (1 + (0.25 / f))
Simplifying the equation, we get:
6 = 1 + (0.25 / f)
5 = 0.25 / f
f = 0.25 / 5
f = 0.05 m or 5 cm
So, the value of the focal length of the eyepiece is 5 cm.
In summary, the magnification of a compound microscope is determined by the magnification of the objective lens and the eyepiece. Given that the final image is formed at the least distance of distinct vision and the magnification of the objective lens is 15, we can calculate the value of the focal length of the eyepiece using the magnification formula. The focal length of the eyepiece is found to be 5 cm.
Magnification = Magnification of Objective Lens × Magnification of Eyepiece
Given that the magnification of the objective lens is 15 and the final image is formed at the least distance of distinct vision, which is 25 cm or 0.25 m, we can calculate the magnification of the eyepiece.
Let's assume the focal length of the eyepiece is f. Now, we can calculate the magnification of the eyepiece using the formula:
Magnification of Eyepiece = 1 + (Distance of Final Image / Focal Length of Eyepiece)
Substituting the given values, we have:
90 = 15 × (1 + (0.25 / f))
Simplifying the equation, we get:
6 = 1 + (0.25 / f)
5 = 0.25 / f
f = 0.25 / 5
f = 0.05 m or 5 cm
So, the value of the focal length of the eyepiece is 5 cm.
In summary, the magnification of a compound microscope is determined by the magnification of the objective lens and the eyepiece. Given that the final image is formed at the least distance of distinct vision and the magnification of the objective lens is 15, we can calculate the value of the focal length of the eyepiece using the magnification formula. The focal length of the eyepiece is found to be 5 cm.
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The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be?
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The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be?.
The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnification of a compound microscope is the final image at the least distance of distinct vision is 90 the magnification of the objective lens is 15 the value of the focal length of the eyepiece will be?.
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