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Two point charges A and B, having charges +Q and −Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomes
- a)4F / 3
- b)F
- c)9F / 16
- d)16F / 9
Correct answer is option 'C'. Can you explain this answer?
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Two point charges A and B, having charges +Q and −Q respectively, are...
Given: Two point charges A and B, having charges Q and −Q respectively, are placed at certain distance apart and force acting between them is F.
To find: If 25% charge of A is transferred to B, then force between the charges becomes
Solution:
Let the distance between the charges be denoted by d.
The force between two charges is given by Coulomb's law as:
F = (1/4πε) * Q1 * Q2 / d^2
where ε is the permittivity of free space.
Initially, the force between the charges is F.
Let's assume that 25% charge of A is transferred to B. Therefore, the new charges of A and B become:
Charge on A = Q - (25/100)Q = (3/4)Q
Charge on B = -Q + (25/100)Q = (-3/4)Q
Using Coulomb's law, the new force between the charges can be calculated as:
F' = (1/4πε) * [(3/4)Q] * [(-3/4)Q] / d^2
F' = (9/16) * (1/4πε) * Q^2 / d^2
F' = (9/16)F
Therefore, the force between the charges becomes 9/16 times the original force after the transfer of charge.
Hence, the correct option is (C) 9F/16.
To find: If 25% charge of A is transferred to B, then force between the charges becomes
Solution:
Let the distance between the charges be denoted by d.
The force between two charges is given by Coulomb's law as:
F = (1/4πε) * Q1 * Q2 / d^2
where ε is the permittivity of free space.
Initially, the force between the charges is F.
Let's assume that 25% charge of A is transferred to B. Therefore, the new charges of A and B become:
Charge on A = Q - (25/100)Q = (3/4)Q
Charge on B = -Q + (25/100)Q = (-3/4)Q
Using Coulomb's law, the new force between the charges can be calculated as:
F' = (1/4πε) * [(3/4)Q] * [(-3/4)Q] / d^2
F' = (9/16) * (1/4πε) * Q^2 / d^2
F' = (9/16)F
Therefore, the force between the charges becomes 9/16 times the original force after the transfer of charge.
Hence, the correct option is (C) 9F/16.
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Community Answer
Two point charges A and B, having charges +Q and −Q respectively, are...
In case I :
In case II :
∴ 
= 
From equations (i) and (ii),
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Two point charges A and B, having charges +Q and −Q respectively, are placed at certain distance apart and force acting between them is F. If 25% charge of A is transferred to B, then force between the charges becomesa)4F / 3b)Fc)9F / 16d)16F / 9Correct answer is option 'C'. Can you explain this answer?
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