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A battery of internal resistance 2 Ω is connected to a variable resistor whose value can vary from 4 Ω to 10 Ω .The resistance is initially set at 4 Ω. If the resistance is now increased then
  • a)
    power consumed by it will decrease.
  • b)
    power consumed by it will increase.
  • c)
    power consumed by it may increase or may decrease.
  • d)
    power consumed will first increase then decrease.
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A battery of internal resistance 2 Ω is connected to a variable resis...
Power is given by, P = I2R
=
Power maximum when r = R. So, the power consumed by it will decrease when we increase the load resistance for R > rR > r.
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Community Answer
A battery of internal resistance 2 Ω is connected to a variable resis...


Explanation:

Background information:
When a resistor is connected to a battery, power is consumed by the resistor. The power consumed by a resistor can be calculated using the formula P = V^2 / R, where P is the power consumed, V is the voltage across the resistor, and R is the resistance of the resistor.

Reasoning:
When the resistance of the variable resistor is increased from 4 Ω to a higher value, the total resistance in the circuit (combination of the internal resistance of the battery and the variable resistor) also increases. This causes the total current flowing through the circuit to decrease. Since power is proportional to current squared (P = I^2 * R), a decrease in current results in a decrease in power consumed by the resistor.

Answer:
Therefore, if the resistance of the variable resistor is increased, the power consumed by it will decrease. This is because as the resistance of the variable resistor increases, the total current flowing through the circuit decreases, leading to a decrease in power consumed by the resistor.
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A battery of internal resistance 2 Ω is connected to a variable resistor whose value can vary from 4 Ω to 10 Ω .The resistance is initially set at 4 Ω. If the resistance is now increased thena)power consumed by it will decrease.b)power consumed by it will increase.c)power consumed by it may increase or may decrease.d)power consumed will first increase then decrease.Correct answer is option 'A'. Can you explain this answer?
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A battery of internal resistance 2 Ω is connected to a variable resistor whose value can vary from 4 Ω to 10 Ω .The resistance is initially set at 4 Ω. If the resistance is now increased thena)power consumed by it will decrease.b)power consumed by it will increase.c)power consumed by it may increase or may decrease.d)power consumed will first increase then decrease.Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A battery of internal resistance 2 Ω is connected to a variable resistor whose value can vary from 4 Ω to 10 Ω .The resistance is initially set at 4 Ω. If the resistance is now increased thena)power consumed by it will decrease.b)power consumed by it will increase.c)power consumed by it may increase or may decrease.d)power consumed will first increase then decrease.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery of internal resistance 2 Ω is connected to a variable resistor whose value can vary from 4 Ω to 10 Ω .The resistance is initially set at 4 Ω. If the resistance is now increased thena)power consumed by it will decrease.b)power consumed by it will increase.c)power consumed by it may increase or may decrease.d)power consumed will first increase then decrease.Correct answer is option 'A'. Can you explain this answer?.
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