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The crystal field stabilisation energy (CFSE) for [CoCl6]4− is 18000cm−1. The CFSE for [CoCl4]2− will be
  • a)
    6000cm−1
  • b)
    16000cm−1
  • c)
    18000cm−1
  • d)
    8000cm−1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The crystal field stabilisation energy (CFSE) for [CoCl6]4− is 18000c...
To determine the crystal field stabilization energy (CFSE) for [CoCl4]2-, we can use the relationship between the CFSE values of different coordination complexes.

The CFSE of [CoCl6]4- is given as 18000 cm-1. This means that the energy difference between the d orbitals in the presence of the ligands is 18000 cm-1.

1. CFSE for [CoCl6]4- = 18000 cm-1

Now, let's consider the [CoCl4]2- complex. This complex has four chloride ligands, which means it has a tetrahedral geometry.

2. CFSE for [CoCl4]2- = ?

Since the geometry is tetrahedral, the splitting of the d orbitals is different compared to an octahedral complex like [CoCl6]4-. In a tetrahedral complex, the t2g set of d orbitals (dxy, dyz, dzx) is lower in energy, while the eg set (dx2-y2, dz2) is higher in energy.

Therefore, we can expect that the CFSE for a tetrahedral complex will be less than the CFSE for an octahedral complex with the same metal ion.

3. CFSE for [CoCl4]2- < cfse="" for="" />

From the given options, the only value that satisfies this relationship is option D, which is 8000 cm-1.

Therefore, the CFSE for [CoCl4]2- is 8000 cm-1.
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Community Answer
The crystal field stabilisation energy (CFSE) for [CoCl6]4− is 18000c...
= 8000cm−1
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The crystal field stabilisation energy (CFSE) for [CoCl6]4− is 18000cm−1. The CFSE for [CoCl4]2− will bea)6000cm−1b)16000cm−1c)18000cm−1d)8000cm−1Correct answer is option 'D'. Can you explain this answer?
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