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Crystal field stabilization energy of CoF3(H2O) is.?
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Crystal field stabilization energy of CoF3(H2O) is.?
Understanding Crystal Field Stabilization Energy (CFSE)
Crystal Field Stabilization Energy (CFSE) is an important concept in coordination chemistry that describes the energy difference between the different arrangements of ligands around a metal ion in a complex.
CoF3(H2O) Complex
- Cobalt (Co) can exist in various oxidation states, but in CoF3(H2O), it is typically in the +3 oxidation state.
- The ligands present are three fluoride ions (F-) and one water molecule (H2O), creating an octahedral geometry.
Electron Configuration
- Cobalt in the +3 oxidation state has the electron configuration of [Ar] 3d6.
- In an octahedral field, the 3d orbitals split into two sets: the lower-energy t2g (dxy, dxz, dyz) and the higher-energy eg (dz2, dx2-y2) orbitals.
Calculating CFSE
- For Co3+ in an octahedral field, the t2g orbitals are filled first.
- With 6 electrons, the configuration in the t2g orbitals will be fully occupied (3 electrons).
CFSE Calculation
- The CFSE can be calculated using the formula: CFSE = (number of electrons in t2g x -0.4Δo) + (number of electrons in eg x +0.6Δo).
- For Co3+:
- t2g = 6 electrons → CFSE = 6 x (-0.4Δo) = -2.4Δo.
- eg = 0 electrons → Contribution = 0.
Total CFSE
- The total CFSE for CoF3(H2O) = -2.4Δo.
- The negative value indicates that the complex is stabilized due to the arrangement of ligands in the crystal field.
Conclusion
- Therefore, the CFSE for CoF3(H2O) is -2.4Δo, highlighting the stabilizing effect of the ligand field around the cobalt ion.
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Crystal field stabilization energy of CoF3(H2O) is.?
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