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Two simple harmonic motions of angular frequency 100 and 1000 rad s–1 have the same displacement amplitude. The ratio of their maximum acceleration is
  • a)
    1 : 103
  • b)
    1 : 104
  • c)
    1 : 10
  • d)
    1 : 102
Correct answer is option 'A'. Can you explain this answer?
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Two simple harmonic motions of angular frequency 100 and 1000 rad s–1...
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Two simple harmonic motions of angular frequency 100 and 1000 rad s–1...
Given Information:
Two simple harmonic motions with angular frequencies of 100 rad/s and 1000 rad/s have the same displacement amplitude.

Ratio of Maximum Acceleration:

Formula:
The maximum acceleration in simple harmonic motion is given by:
\(a_{max} = \omega^2 A\)
where:
\(a_{max}\) = Maximum acceleration
\(\omega\) = Angular frequency
\(A\) = Displacement amplitude

Calculations:
For the motion with an angular frequency of 100 rad/s:
\(a_{max1} = (100)^2 A = 10000A\)
For the motion with an angular frequency of 1000 rad/s:
\(a_{max2} = (1000)^2 A = 1000000A\)

Ratio of Maximum Acceleration:
\(\frac{a_{max2}}{a_{max1}} = \frac{1000000A}{10000A} = 100\)
Therefore, the ratio of the maximum accelerations of the two motions is 1:100, which corresponds to option 'A'.
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Two simple harmonic motions of angular frequency 100 and 1000 rad s–1 have the same displacement amplitude. The ratio of their maximum acceleration isa)1 : 103b)1 : 104c)1 : 10d)1 : 102Correct answer is option 'A'. Can you explain this answer?
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