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The displacement of a particle along the x-axis is given by x = asin2ωt. The motion of the particle corresponds to
  • a)
    Simple harmonic motion of frequency ω/π
  • b)
    Simple harmonic motion of frequency 3ω/2π
  • c)
    Non simple harmonic motion
  • d)
    Simple harmonic motion of frequency ω/2π
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The displacement of a particle along the x-axis is given by x = asin2...
Explanation:
Given:
The displacement of the particle along the x-axis is given by x = asin2ωt.
Analysis:
To determine the nature of the motion, we need to analyze the given equation.
Simple Harmonic Motion:
In simple harmonic motion, the displacement of the particle is given by x = A sin(ωt + φ), where A is the amplitude, ω is the angular frequency, t is the time, and φ is the phase angle.
Comparison:
Comparing the given equation x = asin2ωt with the equation for simple harmonic motion x = A sin(ωt + φ), we can see that the given equation matches the form of simple harmonic motion with A = a, ω = 2ω, and φ = 0.
Frequency:
The frequency of simple harmonic motion is given by f = ω/2π. In this case, the frequency is 2ω/(2π) = ω/π.
Conclusion:
Therefore, the motion of the particle corresponds to simple harmonic motion of frequency ω/π. Hence, the correct answer is option 'A'.
Free Test
Community Answer
The displacement of a particle along the x-axis is given by x = asin2...
x = asin2ωt
On comparing (1)1 with the standard sinusoidal equation of SHM, we get,
We conclude that the given equation represents the simple harmonic motion of amplitude a/2 and angular frequency 2ω.
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The displacement of a particle along the x-axis is given by x = asin2ωt. The motion of the particle corresponds toa)Simple harmonic motion of frequency ω/πb)Simple harmonic motion of frequency 3ω/2πc)Non simple harmonic motiond)Simple harmonic motion of frequency ω/2πCorrect answer is option 'A'. Can you explain this answer?
Question Description
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