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A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl freezes at - 0.00732oC. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be :
  • a)
    3
  • b)
    4
  • c)
    1
  • d)
    2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl fr...
The number of moles of ions produced by 1 mole of ionic compound = i
Applying,
ΔTf = i × Kf × m
0.00732 = i × ×1.86 × 0.002
Thus number of ions = 2
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Community Answer
A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl fr...

Explanation:

Given Data:
- Freezing point depression (ΔTf) = -0.00732oC
- Molality (m) = 0.0020 m

Formula:
ΔTf = i * Kf * m

Calculations:
- Given that the freezing point depression is caused by the dissociation of the ionic compound [Co(NH3)5(NO2)]Cl into ions, we can say that 1 mol of the ionic compound produces 'i' moles of ions.
- The formula weight of [Co(NH3)5(NO2)]Cl is 209.02 g/mol. Therefore, the molality (m) can be calculated as follows:
m = (moles of solute) / (kg of solvent)
moles of solute = (0.0020 m) * (1 kg) = 0.0020 mol
- Using the formula ΔTf = i * Kf * m, we can solve for 'i':
-0.00732 = i * Kf * 0.0020
i = -0.00732 / (Kf * 0.0020)

Conclusion:
- Since the number of moles of ions which 1 mol of the ionic compound produces on being dissolved in water will be equal to 'i', the correct answer is option 'D' (2).
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A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl freezes at - 0.00732oC. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be :a)3b)4c)1d)2Correct answer is option 'D'. Can you explain this answer?
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A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl freezes at - 0.00732oC. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be :a)3b)4c)1d)2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl freezes at - 0.00732oC. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be :a)3b)4c)1d)2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.0020 m aqueous solution of an ionic compound [Co(NH3)5(NO2)]Cl freezes at - 0.00732oC. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be :a)3b)4c)1d)2Correct answer is option 'D'. Can you explain this answer?.
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