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In a chemical reaction, the rate constant for the backward reaction is 7.5 × 10–4 and the equilibrium constant is 1.5. The rate constant for the forward reaction is -
  • a)
    5 × 10–4
  • b)
    2 × 10–3
  • c)
    1.125 × 10–3
  • d)
    9.0 × 10–4
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a chemical reaction, the rate constant for the backward reaction i...
Apply the formula, K = Kf/Kb
we get, Kf = 1.5 × 7.5 × 10−4 = 1.125 × 10−3
Free Test
Community Answer
In a chemical reaction, the rate constant for the backward reaction i...

Given Information:
- Rate constant for backward reaction (kbackward) = 7.5 × 10–4
- Equilibrium constant (Kc) = 1.5

To Find:
Rate constant for the forward reaction (kforward)

Solution:

- The equilibrium constant (Kc) is given by the ratio of rate constants for the forward and backward reactions:
Kc = kforward / kbackward

- Substitute the given values into the equation:
1.5 = kforward / 7.5 × 10–4

- Rearrange the equation to solve for kforward:
kforward = 1.5 × 7.5 × 10–4
kforward = 1.125 × 10–3

Therefore, the rate constant for the forward reaction is 1.125 × 10–3, which corresponds to option 'C'.
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In a chemical reaction, the rate constant for the backward reaction is 7.5 × 10–4 and the equilibrium constant is 1.5. The rate constant for the forward reaction is -a)5 × 10–4b)2 × 10–3c)1.125 × 10–3d)9.0 × 10–4Correct answer is option 'C'. Can you explain this answer?
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