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A force of 170 N is applied to a body of mass 5 kg which raised it vertically to a height of 10 m. The velocity of the body at this height will be
- a)37 m−s⁻1
- b)22 m−s⁻1
- c)15 m−s⁻1
- d)9.8 m−s⁻1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A force of 170 N is applied to a body of mass 5 kg which raised it ver...
/s
b)20 m/s
c)10 m/s
d)5 m/s
We can use the work-energy principle to solve this problem. The work done by the force in raising the body is equal to the change in its potential energy.
Work done = force x distance = 170 N x 10 m = 1700 J
Change in potential energy = mgh = 5 kg x 9.8 m/s^2 x 10 m = 490 J
Equating the two, we get:
1700 J = 490 J + 1/2 mv^2
Solving for v, we get:
v = sqrt((1700 J - 490 J) x 2 / 5 kg) = 37 m/s (approx)
Therefore, the velocity of the body at a height of 10 m is approximately 37 m/s. Option (a) is correct.
b)20 m/s
c)10 m/s
d)5 m/s
We can use the work-energy principle to solve this problem. The work done by the force in raising the body is equal to the change in its potential energy.
Work done = force x distance = 170 N x 10 m = 1700 J
Change in potential energy = mgh = 5 kg x 9.8 m/s^2 x 10 m = 490 J
Equating the two, we get:
1700 J = 490 J + 1/2 mv^2
Solving for v, we get:
v = sqrt((1700 J - 490 J) x 2 / 5 kg) = 37 m/s (approx)
Therefore, the velocity of the body at a height of 10 m is approximately 37 m/s. Option (a) is correct.
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