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Consider the circuit shown with an ideal long channel nMOSFET (enhancement-mode, substrate is connected to the source). The transistor is appropriately biased in the saturation region with VGG and VDD such that it acts as a linear amplifier. vi is the small-signal ac input voltage. vA and vB represent the small-signal voltages at the nodes A and B, respectively. The value of vA/vB is _______. (round off to one decimal place)
  • a)
    -1.9
  • b)
    -2.1
Correct answer is between '-1.9,-2.1'. Can you explain this answer?
Most Upvoted Answer
Consider the circuit shown with an ideal long channel nMOSFET (enhanc...
Method 1
Given circuit is shown below,
From above figure,
IG = 0
So, ID = IS
AC equivalent circuit :
(i) All capacitors are short circuited.
(ii) All DC voltage sources are replaced by short circuit.
(iii)All DC current sources are replaced by open circuit.
Small signal equivalent circuit is shown below,
Voltage at A, vA = -RDgmVgs ………..(i)
Voltage at B, vB = RsgmVgs ……..(ii)
Hence, the correct answer is – 2.
Method 2
Case 1 : Consider output at point-A only i.e. vA , so given circuit behave as common source amplifier ,whose small signal equivalent circuit is shown below,
Apply KVL in loop-1,
Voltage at point-A is,
Case 2 : Consider output at point-B only i.e. vB so given circuit behave as common drain amplifier, whose
small signal equivalent circuit is shown below,
Apply KVL is loop-1,
Voltage at point-B,
From equation (iii) and (vi),
Hence, the correct answer is – 2.
Free Test
Community Answer
Consider the circuit shown with an ideal long channel nMOSFET (enhanc...
Method 1
Given circuit is shown below,
From above figure,
IG = 0
So, ID = IS
AC equivalent circuit :
(i) All capacitors are short circuited.
(ii) All DC voltage sources are replaced by short circuit.
(iii)All DC current sources are replaced by open circuit.
Small signal equivalent circuit is shown below,
Voltage at A, vA = -RDgmVgs ………..(i)
Voltage at B, vB = RsgmVgs ……..(ii)
Hence, the correct answer is – 2.
Method 2
Case 1 : Consider output at point-A only i.e. vA , so given circuit behave as common source amplifier ,whose small signal equivalent circuit is shown below,
Apply KVL in loop-1,
Voltage at point-A is,
Case 2 : Consider output at point-B only i.e. vB so given circuit behave as common drain amplifier, whose
small signal equivalent circuit is shown below,
Apply KVL is loop-1,
Voltage at point-B,
From equation (iii) and (vi),
Hence, the correct answer is – 2.
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Consider the circuit shown with an ideal long channel nMOSFET (enhancement-mode, substrate is connected to the source). The transistor is appropriately biased in the saturation region with VGG and VDD such that it acts as a linear amplifier. vi is the small-signal ac input voltage. vA and vB represent the small-signal voltages at the nodes A and B, respectively. The value of vA/vB is _______. (round off to one decimal place)a)-1.9b)-2.1Correct answer is between '-1.9,-2.1'. Can you explain this answer?
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