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An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.?
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An olefinic hydrocarbon A adds Cl₂ to give compound B which when treat...
Reaction Pathway:
1. Addition of Cl2 to Olefinic Hydrocarbon A
The olefinic hydrocarbon A undergoes addition reaction with Cl2 to give compound B. This reaction is an example of electrophilic addition reaction.
2. Treatment of B with Sodamide to form C
Compound B is treated with sodamide to give hydrocarbon C. Sodamide is a strong base and it abstracts the acidic proton from the compound B to form compound C.
3. Treatment of C with Dilute H2SO4 in presence of HgSO4 to form D
Hydrocarbon C is treated with dilute H2SO4 in the presence of HgSO4 to give compound D. This reaction is an example of acid-catalyzed dehydration.
4. Reaction of D with Alkaline Hypochlorite to form E
Compound D is reacted with alkaline hypochlorite to give acid E. This reaction is an example of oxidative cleavage of the carbon-carbon double bond.
5. Reduction of D with LIAIH4 to form F
Compound D is reduced with LIAIH4 to give hydrocarbon F. LIAIH4 is a powerful reducing agent and it reduces the carbonyl group of compound D to form hydrocarbon F.
6. Dehydration of F with Al2O3 to form G
Hydrocarbon F is dehydrated with Al2O3 to give hydrocarbon G. Al2O3 is a dehydrating agent and it removes the water molecule from hydrocarbon F to form hydrocarbon G.
7. Ozonolysis of G to form 2 molecules of Acetaldehyde
Hydrocarbon G is subjected to ozonolysis to give two molecules of acetaldehyde. Ozonolysis is a powerful oxidative cleavage reaction that cleaves the carbon-carbon double bond of hydrocarbon G to form two molecules of acetaldehyde.
Explanation:
The given reaction pathway involves a series of chemical transformations of an olefinic hydrocarbon A to form hydrocarbon G. The initial step involves the addition of Cl2 to the carbon-carbon double bond of A to form compound B. This reaction is an example of electrophilic addition reaction.
Compound B is then treated with sodamide to form hydrocarbon C. Sodamide is a strong base and it abstracts the acidic proton from the compound B to form compound C.
Hydrocarbon C is then subjected to acid-catalyzed dehydration to give compound D. The presence of HgSO4 as a catalyst enhances the rate of the dehydration reaction.
Compound D is then reacted with alkaline hypochlorite to give acid E. This reaction involves the oxidative cleavage of the carbon-carbon double bond of compound D.
Compound D is then reduced with LIAIH4 to form hydrocarbon F. LIAIH4 is a powerful reducing agent and it reduces the carbonyl group of compound D to form hydrocarbon F.
Hydrocarbon F is then dehydrated with Al2O3 to give hydrocarbon G. Al2O3 is a dehydrating agent and it removes the water molecule from hydrocarbon F to form hydrocarbon G.
Hydrocarbon G is subjected to
1. Addition of Cl2 to Olefinic Hydrocarbon A
The olefinic hydrocarbon A undergoes addition reaction with Cl2 to give compound B. This reaction is an example of electrophilic addition reaction.
2. Treatment of B with Sodamide to form C
Compound B is treated with sodamide to give hydrocarbon C. Sodamide is a strong base and it abstracts the acidic proton from the compound B to form compound C.
3. Treatment of C with Dilute H2SO4 in presence of HgSO4 to form D
Hydrocarbon C is treated with dilute H2SO4 in the presence of HgSO4 to give compound D. This reaction is an example of acid-catalyzed dehydration.
4. Reaction of D with Alkaline Hypochlorite to form E
Compound D is reacted with alkaline hypochlorite to give acid E. This reaction is an example of oxidative cleavage of the carbon-carbon double bond.
5. Reduction of D with LIAIH4 to form F
Compound D is reduced with LIAIH4 to give hydrocarbon F. LIAIH4 is a powerful reducing agent and it reduces the carbonyl group of compound D to form hydrocarbon F.
6. Dehydration of F with Al2O3 to form G
Hydrocarbon F is dehydrated with Al2O3 to give hydrocarbon G. Al2O3 is a dehydrating agent and it removes the water molecule from hydrocarbon F to form hydrocarbon G.
7. Ozonolysis of G to form 2 molecules of Acetaldehyde
Hydrocarbon G is subjected to ozonolysis to give two molecules of acetaldehyde. Ozonolysis is a powerful oxidative cleavage reaction that cleaves the carbon-carbon double bond of hydrocarbon G to form two molecules of acetaldehyde.
Explanation:
The given reaction pathway involves a series of chemical transformations of an olefinic hydrocarbon A to form hydrocarbon G. The initial step involves the addition of Cl2 to the carbon-carbon double bond of A to form compound B. This reaction is an example of electrophilic addition reaction.
Compound B is then treated with sodamide to form hydrocarbon C. Sodamide is a strong base and it abstracts the acidic proton from the compound B to form compound C.
Hydrocarbon C is then subjected to acid-catalyzed dehydration to give compound D. The presence of HgSO4 as a catalyst enhances the rate of the dehydration reaction.
Compound D is then reacted with alkaline hypochlorite to give acid E. This reaction involves the oxidative cleavage of the carbon-carbon double bond of compound D.
Compound D is then reduced with LIAIH4 to form hydrocarbon F. LIAIH4 is a powerful reducing agent and it reduces the carbonyl group of compound D to form hydrocarbon F.
Hydrocarbon F is then dehydrated with Al2O3 to give hydrocarbon G. Al2O3 is a dehydrating agent and it removes the water molecule from hydrocarbon F to form hydrocarbon G.
Hydrocarbon G is subjected to
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An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.?
Question Description
An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.?.
An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.?.
Solutions for An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? in English & in Hindi are available as part of our courses for NEET.
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An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.?, a detailed solution for An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? has been provided alongside types of An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? theory, EduRev gives you an
ample number of questions to practice An olefinic hydrocarbon A adds Cl₂ to give compound B which when treated with sodamide gives hydrocarbon C. C is treated with dil. H₂SO, in presence of HgSO4 and then D is obtained. D on reaction with alkaline hypochlorite gives an acid E. D on reduction with LIAIH4 gives F which on dehydration with Al2O3 gives hydrocarbon G which is isomeric with A and which on ozonolysis gives 2 molecules of acetaldehyde. Explain the reaction.? tests, examples and also practice NEET tests.
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