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In a Young's double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is:
  • a)
    8
  • b)
    9
  • c)
    12
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a Youngs double slit experiment, a student observes 8 fringes in a ...
y = (nλ) (D/d)
n1λ1 = n2λ2
(8) (600 nm) = n2(400)
n2 = 12 
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Community Answer
In a Youngs double slit experiment, a student observes 8 fringes in a ...
Concept:
Young's double-slit experiment involves passing light through two closely spaced slits and observing the resulting interference pattern on a screen. The interference pattern is formed due to the superposition of light waves from the two slits, resulting in constructive and destructive interference. The formula for calculating the fringe separation (distance between two consecutive fringes) is given by:

y = λL / d

where y is the fringe separation, λ is the wavelength of light, L is the distance between the slits and the screen, and d is the distance between the slits.

Given:
Wavelength of light used: 600 nm
Number of fringes observed: 8

Calculation:
To find the number of fringes observed when the wavelength is changed to 400 nm, we can use the formula:

y = λL / d

Since the distance between the slits and the screen (L) and the distance between the slits (d) remain constant in this case, we can write:

y1 / y2 = λ1 / λ2

where y1 is the fringe separation for the original wavelength (600 nm), y2 is the fringe separation for the new wavelength (400 nm), λ1 is the original wavelength (600 nm), and λ2 is the new wavelength (400 nm).

Let's substitute the known values into the equation:

y1 / y2 = 600 nm / 400 nm

Simplifying the equation:

y1 / y2 = 3/2

Since the fringe separation is directly proportional to the number of fringes, we can say that:

Number of fringes observed for the new wavelength / Number of fringes observed for the original wavelength = 3/2

Let the number of fringes observed for the new wavelength be x. Therefore, we can write:

x / 8 = 3/2

Cross-multiplying and solving for x:

2x = 8 * 3
2x = 24
x = 12

Therefore, the number of fringes observed with the new wavelength of 400 nm is 12.

Hence, the correct answer is option C) 12.
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In a Youngs double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is:a)8b)9c)12d)6Correct answer is option 'C'. Can you explain this answer?
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In a Youngs double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is:a)8b)9c)12d)6Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a Youngs double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is:a)8b)9c)12d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Youngs double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is:a)8b)9c)12d)6Correct answer is option 'C'. Can you explain this answer?.
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