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In a Young’s experiment, two coherent sources are placed 0.90 mm apart and the fringes are observed one metre away. If it produces the second dark fringe at a distance of 1 mm from the central fringe, then wavelength of monochromatic light used would be 
  • a)
    60 x 10cm
  • b)
    10 x 10-4 cm
  • c)
    10 x 10-5 cm
  • d)
    6 x 10-5 cm
Correct answer is option 'D'. Can you explain this answer?
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In a Young’s experiment, two coherent sources are placed 0.90 mm...
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In a Young’s experiment, two coherent sources are placed 0.90 mm...
Given Data:
Distance between the two coherent sources (d) = 0.90 mm = 0.90 x 10^-3 m
Distance to the screen (L) = 1 m
Distance of second dark fringe from central fringe (x) = 1 mm = 1 x 10^-3 m

Formula:
The formula to calculate the distance between the fringes in Young's double-slit experiment is given by:
x = λL/d

Calculation:
Given x = 1 x 10^-3 m, L = 1 m, d = 0.90 x 10^-3 m
Substitute the values in the formula:
1 x 10^-3 = λ x 1 / 0.90 x 10^-3
1 x 10^-3 = λ / 0.90
λ = 1 x 10^-3 x 0.90
λ = 9 x 10^-4 m
λ = 9 x 10^-4 x 10^2 cm
λ = 9 x 10^-2 cm
λ = 6 x 10^-5 cm
Therefore, the wavelength of the monochromatic light used in the experiment is 6 x 10^-5 cm, which corresponds to option 'D'.
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In a Young’s experiment, two coherent sources are placed 0.90 mm apart and the fringes are observed one metre away. If it produces the second dark fringe at a distance of 1 mm from the central fringe, then wavelength of monochromatic light used would bea)60 x 104cmb)10 x 10-4 cmc)10 x10-5cmd)6 x 10-5cmCorrect answer is option 'D'. Can you explain this answer?
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