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Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.?
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Two resistances X and Y in the two gaps of a meter-bridge gives a null...
Explanation:
Meter Bridge Experiment
Meter bridge experiment is an experiment which is used to find the resistance of a wire. In this experiment, the resistance of an unknown resistor is compared with the known resistance of a wire.
Null Point
The point on the wire where there is no flow of current is known as the null point. At this point, the potential difference across the two points on the wire is zero.
Given
Let X and Y be the resistance in the two gaps of the meter bridge. Let the length of the wire be L. The null point divides the wire in the ratio 2:3, which means that the distance of the null point from X is 2L/5 and the distance of the null point from Y is 3L/5.
Equations
Using the principle of Wheatstone bridge, we can write the following equations:
X/(L/5) = Y/(4L/5) ----- (1)
X/(2L/5) = Y/(3L/5) ----- (2)
From equation (1), we get X = (L/5) Y/(4L/5) = Y/4
From equation (2), we get X = (2L/5) Y/(3L/5) = (4/3)Y
Equating the above two equations, we get:
Y/4 = (4/3)Y
Y = 16Ω
X = Y/4 = 4Ω
Increased Resistance
When each resistance is increased by 3Ω, the new resistance of X is 7Ω and the new resistance of Y is 19Ω.
Equations for New Null Point
Let the new null point be at a distance of x from X. Then, the new null point will be at a distance of (L-x) from Y.
Using the principle of Wheatstone bridge, we can write the following equations:
7/(L-x) = 19/x ----- (3)
7/(5L/6 - x) = 19/(L/6 + x) ----- (4)
From equation (3), we get x = 3L/8
From equation (4), we get x = L/4
Answer
Therefore, the value of X is 4Ω and the value of Y is 16Ω.
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Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.?
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Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.?.
Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two resistances X and Y in the two gaps of a meter-bridge gives a null point dividing the wire in the ratio 2:3. If each resistance is increased by 3Ω, the null point divides the wire in the ratio 5:6, calculate the value of X and Y.?.
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