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Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve?
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Flask A of volume 10 liter containing 20 gram of H2 and flask B of vol...
**Composition of H2 gas in Flask B after opening the valve**
To determine the composition of H2 gas in Flask B after opening the valve, we need to consider the principle of partial pressures and the ideal gas law.
**1. Calculating the initial number of moles of H2 and CO2:**
- The number of moles of H2 can be calculated using the formula:
Moles of H2 = Mass of H2 / Molar mass of H2
Moles of H2 = 20 g / 2 g/mol (molar mass of H2)
Moles of H2 = 10 mol
- The number of moles of CO2 can be calculated using the formula:
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Moles of CO2 = 88 g / 44 g/mol (molar mass of CO2)
Moles of CO2 = 2 mol
**2. Calculating the total number of moles after connecting the flasks:**
- Since the flasks are connected by a connector with negligible volume, the total volume becomes the sum of the individual volumes: 10 L + 10 L = 20 L.
- According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of moles.
- Therefore, the total number of moles of the gas mixture is the sum of the moles of H2 and CO2 from both flasks: 10 mol + 2 mol = 12 mol.
**3. Calculating the composition of H2 gas in Flask B:**
- The composition of H2 gas in Flask B can be determined by calculating the mole fraction of H2 in the total gas mixture.
- The mole fraction of a gas is the ratio of the number of moles of that gas to the total number of moles.
- Mole fraction of H2 in Flask B = Moles of H2 in Flask B / Total moles of the gas mixture
- Since Flask B initially contained 2 moles of CO2, the moles of H2 in Flask B after opening the valve would be the same as the original amount of H2 in Flask A, which is 10 mol.
- Mole fraction of H2 in Flask B = 10 mol / 12 mol = 0.833
**Explanation:**
After opening the valve, the H2 gas from Flask A will mix with the CO2 gas from Flask B. The total number of moles of the gas mixture will be 12 mol. Therefore, the composition of H2 gas in Flask B after opening the valve will be 0.833 (or 83.3%). This means that approximately 83.3% of the gas in Flask B will be composed of H2 gas.
To determine the composition of H2 gas in Flask B after opening the valve, we need to consider the principle of partial pressures and the ideal gas law.
**1. Calculating the initial number of moles of H2 and CO2:**
- The number of moles of H2 can be calculated using the formula:
Moles of H2 = Mass of H2 / Molar mass of H2
Moles of H2 = 20 g / 2 g/mol (molar mass of H2)
Moles of H2 = 10 mol
- The number of moles of CO2 can be calculated using the formula:
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Moles of CO2 = 88 g / 44 g/mol (molar mass of CO2)
Moles of CO2 = 2 mol
**2. Calculating the total number of moles after connecting the flasks:**
- Since the flasks are connected by a connector with negligible volume, the total volume becomes the sum of the individual volumes: 10 L + 10 L = 20 L.
- According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of moles.
- Therefore, the total number of moles of the gas mixture is the sum of the moles of H2 and CO2 from both flasks: 10 mol + 2 mol = 12 mol.
**3. Calculating the composition of H2 gas in Flask B:**
- The composition of H2 gas in Flask B can be determined by calculating the mole fraction of H2 in the total gas mixture.
- The mole fraction of a gas is the ratio of the number of moles of that gas to the total number of moles.
- Mole fraction of H2 in Flask B = Moles of H2 in Flask B / Total moles of the gas mixture
- Since Flask B initially contained 2 moles of CO2, the moles of H2 in Flask B after opening the valve would be the same as the original amount of H2 in Flask A, which is 10 mol.
- Mole fraction of H2 in Flask B = 10 mol / 12 mol = 0.833
**Explanation:**
After opening the valve, the H2 gas from Flask A will mix with the CO2 gas from Flask B. The total number of moles of the gas mixture will be 12 mol. Therefore, the composition of H2 gas in Flask B after opening the valve will be 0.833 (or 83.3%). This means that approximately 83.3% of the gas in Flask B will be composed of H2 gas.
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Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve?
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Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve?.
Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Flask A of volume 10 liter containing 20 gram of H2 and flask B of volume 10 litre containing 88 gram CO2 are connected by a connector having negligible volume. When valve of the connector is opened what is the composition of H2 gas in flask B after openening the valve?.
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