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5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer?
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5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsiu...
Ya.. 100 degree celcius.. energy released by steam whileconverting into water is much more than absorbed by ice to cnvrt into water nd thn rising of temp of water.. (5*80+5*1*100) is less thn (5*540).so some steam will be left.. nd only some amount is used.. so ans is 100 degre..
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5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsiu...
Problem:
5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius. What is the final temperature of the mixture?
Solution:
Step 1: Calculate heat absorbed by ice to reach its melting point
Heat absorbed by ice = mass of ice x specific heat of ice x change in temperature
Heat absorbed by ice = 5g x 2.09 J/g°C x (0°C - (-0.00°C))
Heat absorbed by ice = 10.45 J
Step 2: Calculate heat absorbed by ice to melt it
Heat absorbed by ice to melt = mass of ice x heat of fusion of ice
Heat absorbed by ice to melt = 5g x 334 J/g
Heat absorbed by ice to melt = 1670 J
Step 3: Calculate heat absorbed by water to reach 100 degree Celsius
Heat absorbed by water = mass of water x specific heat of water x change in temperature
Heat absorbed by water = 5g x 4.18 J/g°C x (100°C - 0°C)
Heat absorbed by water = 2090 J
Step 4: Calculate heat absorbed by steam to condense it
Heat absorbed by steam to condense = mass of steam x heat of vaporization of water
Heat absorbed by steam to condense = 5g x 2260 J/g
Heat absorbed by steam to condense = 11300 J
Step 5: Calculate heat released by water when it cools down to the final temperature
Heat released by water = mass of water x specific heat of water x change in temperature
Heat released by water = 10g x 4.18 J/g°C x (100°C - final temperature)
Step 6: Equate the total heat absorbed and heat released to find the final temperature
Total heat absorbed = Heat absorbed by ice to reach its melting point + Heat absorbed by ice to melt + Heat absorbed by water to reach 100 degree Celsius + Heat absorbed by steam to condense
Total heat absorbed = 10.45 J + 1670 J + 2090 J + 11300 J
Total heat absorbed = 15070 J
Total heat released = Heat released by water when it cools down to the final temperature
Total heat released = 10g x 4.18 J/g°C x (100°C - final temperature)
Total heat released = 4180 J x (100°C - final temperature)
Equating heat absorbed and heat released:
15070 J = 4180 J x (100°C - final temperature)
Final temperature = 35.94°C
Answer:
The final temperature of the mixture is 35.94°C
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5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer?
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5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer?.
5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 5g ice at 0 degree Celsius is mixed with 5g steam at 100 degree Celsius.what is the final temp of the mixture? plz answer?.
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